Momentum Calculator
Calculate momentum, mass, or velocity using p = mv. Includes elastic and inelastic collision calculations.
Momentum Calculator
Solve for:
Momentum Formula:
p = m × v
Momentum (kg·m/s) = Mass (kg) × Velocity (m/s)
Momentum
10000.00 kg·m/s
Impulse & Force to Stop:
Collision Calculator
Object 1
Momentum: 10000.00 kg·m/s
Object 2
Momentum: -7500.00 kg·m/s
Collision Type:
Total Initial Momentum
2500.00 kg·m/s
Final Velocity
1.00 m/s
Energy Lost
67500 J (98.2%)
Understanding Momentum
Conservation of Momentum
Total momentum is conserved in all collisions when no external forces act. p₁ᵢ + p₂ᵢ = p₁f + p₂f
Impulse-Momentum Theorem
Impulse equals change in momentum: J = Δp = F × Δt This explains why airbags work - extending collision time reduces force.
What is Momentum?
Momentum is the product of an object's mass and velocity. It represents the "quantity of motion" and is a vector quantity pointing in the direction of velocity.
| Property | Symbol | Unit | Description |
|---|---|---|---|
| Momentum | p | kg·m/s | Mass times velocity |
| Mass | m | kg | Amount of matter |
| Velocity | v | m/s | Speed with direction |
| Impulse | J | N·s | Change in momentum |
Key insight: A slowly moving heavy truck can have the same momentum as a fast-moving motorcycle.
Momentum Formula
Where:
- p= Momentum (kg·m/s)
- m= Mass (kg)
- v= Velocity (m/s)
Conservation of Momentum
The Law of Conservation of Momentum states that the total momentum of an isolated system remains constant:
| Condition | Mathematical Form | Implication |
|---|---|---|
| Isolated system | p_total = constant | No external forces |
| Before/after collision | Σp_before = Σp_after | Total momentum conserved |
| Two objects | m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂' | Individual momenta can change |
Applications: Collisions, explosions, recoil, rocket propulsion all rely on conservation of momentum.
Conservation of Momentum
Where:
- m₁, m₂= Masses of objects
- v₁, v₂= Initial velocities
- v₁', v₂'= Final velocities
Impulse and Momentum Change
Impulse is the change in momentum, caused by a force acting over time:
| Relationship | Formula | Unit |
|---|---|---|
| Impulse definition | J = FΔt | N·s |
| Impulse-momentum theorem | J = Δp = p_f - p_i | kg·m/s |
| From Newton's 2nd law | F = Δp/Δt = ma | N |
Practical implication: To change momentum gently (less force), increase the time. This is why cars have crumple zones and why you bend your knees when landing.
Impulse-Momentum Theorem
Where:
- J= Impulse (N·s or kg·m/s)
- F= Average force (N)
- Δt= Time interval (s)
- Δp= Change in momentum
Types of Collisions
Collisions are classified by what quantities are conserved:
| Type | Momentum | Kinetic Energy | Example |
|---|---|---|---|
| Elastic | Conserved | Conserved | Billiard balls (nearly) |
| Inelastic | Conserved | NOT conserved | Car crash |
| Perfectly inelastic | Conserved | Maximum loss | Objects stick together |
| Explosion | Conserved | Increases | Firework bursting |
Collision Equations
Where:
- v'= Final common velocity (inelastic)
- KE= Kinetic energy (½mv²)
Elastic Collision Formulas
For perfectly elastic collisions in one dimension:
| Scenario | Formula for v₁' | Formula for v₂' |
|---|---|---|
| General case | v₁' = ((m₁-m₂)v₁ + 2m₂v₂)/(m₁+m₂) | v₂' = ((m₂-m₁)v₂ + 2m₁v₁)/(m₁+m₂) |
| Equal masses | v₁' = v₂ | v₂' = v₁ |
| Object 2 at rest | v₁' = (m₁-m₂)v₁/(m₁+m₂) | v₂' = 2m₁v₁/(m₁+m₂) |
| m₁ >> m₂, v₂=0 | v₁' ≈ v₁ | v₂' ≈ 2v₁ |
| m₁ << m₂, v₂=0 | v₁' ≈ -v₁ | v₂' ≈ 0 |
Real-World Applications
Momentum principles are used in many technologies and safety systems:
| Application | Principle Used | How It Works |
|---|---|---|
| Airbags | Impulse (FΔt = Δp) | Increase Δt to reduce F |
| Rocket propulsion | Conservation | Expel mass backward, gain momentum forward |
| Gun recoil | Conservation | Bullet momentum forward = gun momentum backward |
| Pool/billiards | Elastic collisions | Transfer momentum and energy |
| Crash testing | Impulse analysis | Design crumple zones |
| Spacecraft docking | Inelastic collision | Objects combine, share momentum |
Angular Momentum
Angular momentum is the rotational analog of linear momentum:
| Quantity | Linear | Angular |
|---|---|---|
| Momentum | p = mv | L = Iω |
| Inertia | Mass (m) | Moment of inertia (I) |
| Velocity | v | Angular velocity (ω) |
| Force relation | F = dp/dt | τ = dL/dt |
| Conservation | If ΣF = 0, p = const | If Στ = 0, L = const |
Example: Figure skaters spin faster when pulling arms in (decreasing I, so ω increases to keep L constant).
Angular Momentum
Where:
- L= Angular momentum (kg·m²/s)
- I= Moment of inertia (kg·m²)
- ω= Angular velocity (rad/s)
- r= Radius (m)
Worked Examples
Calculate Momentum
Problem:
A 1,200 kg car travels at 25 m/s. What is its momentum?
Solution Steps:
- 1Identify values: m = 1,200 kg, v = 25 m/s
- 2Apply formula: p = mv
- 3Calculate: p = 1,200 × 25 = 30,000 kg·m/s
Result:
Momentum = 30,000 kg·m/s
Perfectly Inelastic Collision
Problem:
A 2 kg ball moving at 5 m/s collides and sticks to a 3 kg ball at rest. Find the final velocity.
Solution Steps:
- 1Total initial momentum: p_i = m₁v₁ + m₂v₂ = 2(5) + 3(0) = 10 kg·m/s
- 2After collision, combined mass: m_total = 2 + 3 = 5 kg
- 3Conservation: p_f = p_i, so (5)v' = 10
- 4Final velocity: v' = 10/5 = 2 m/s
Result:
Final velocity = 2 m/s in original direction
Impulse from Force
Problem:
A bat exerts 15,000 N on a 0.145 kg baseball for 0.002 s. What velocity change occurs?
Solution Steps:
- 1Calculate impulse: J = FΔt = 15,000 × 0.002 = 30 N·s
- 2Impulse equals momentum change: J = mΔv
- 3Solve for Δv: Δv = J/m = 30/0.145 = 207 m/s
- 4This is the change in velocity (could reverse direction)
Result:
Velocity change = 207 m/s (≈ 463 mph)
Tips & Best Practices
- ✓Choose a positive direction and stick with it throughout the problem
- ✓Momentum is ALWAYS conserved in isolated systems (no external forces)
- ✓Kinetic energy is only conserved in perfectly elastic collisions
- ✓For perfectly inelastic collisions (objects stick), use v' = (m₁v₁ + m₂v₂)/(m₁+m₂)
- ✓Impulse = Force × Time = Change in momentum (J = FΔt = Δp)
- ✓To reduce impact force, increase impact time (padding, crumple zones)
- ✓1 kg·m/s = 1 N·s (units of momentum and impulse are equivalent)
Frequently Asked Questions
Sources & References
Last updated: 2026-01-22