Z-Score Calculator

Calculate z-scores, probabilities, and percentiles for normal distributions. Find how many standard deviations a value is from the mean.

Calculate Z-Score

Calculate:

10
0.150

Formula:

z = (x - μ) / σ

Z-Score

1.0000

Between 1-2 standard deviations (less common)

⬅️P(X ≤ x)
84.1345%
➡️P(X > x)
15.8655%
📊Percentile
84.13th
📍X Value
85.0000

Normal Distribution:

-4σ-2σμ+2σ+4σ

Empirical Rule:

±1σ (65.00 to 85.00): 68.27% of data

±2σ (55.00 to 95.00): 95.45% of data

±3σ: 99.73% of data

Z-Score Reference Table

z = -3

P(X≤x)

0.13%

z = -2

P(X≤x)

2.28%

z = -1

P(X≤x)

15.87%

z = 0

P(X≤x)

50.00%

z = 1

P(X≤x)

84.13%

z = 2

P(X≤x)

97.72%

z = 3

P(X≤x)

99.87%

Understanding Z-Scores

A z-score (also called a standard score) tells you how many standard deviations a value is from the mean. A z-score of 0 means the value equals the mean. Positive z-scores indicate values above the mean, while negative z-scores indicate values below the mean. Z-scores are useful for comparing values from different distributions or determining how unusual a particular value is.

What Is a Z-Score?

A Z-score (also called a standard score) tells you how many standard deviations a value is from the mean. It standardizes data, allowing you to compare values from different distributions and calculate probabilities using the normal distribution. Z-scores are fundamental to statistical testing, quality control, and understanding relative position.

Z-ScoreMeaningPercentile (Normal)
z = -33 SDs below mean0.13% (rare)
z = -22 SDs below mean2.28%
z = -11 SD below mean15.87%
z = 0At the mean50% (median)
z = 11 SD above mean84.13%
z = 22 SDs above mean97.72%
z = 33 SDs above mean99.87% (rare)

Z-Score Formula

z = (x - μ) / σ

Where:

  • z= Z-score (standard score)
  • x= Raw value (data point)
  • μ= Population mean
  • σ= Population standard deviation

Interpreting Z-Scores

Z-scores tell you the relative position of a value within a distribution. Positive z-scores are above average; negative z-scores are below average. The magnitude tells you how unusual the value is.

Z-Score RangeInterpretationIn Normal Distribution
|z| < 1Typical, within 1 SDAbout 68% of values
1 ≤ |z| < 2Somewhat unusualAbout 27% of values
2 ≤ |z| < 3UnusualAbout 4.5% of values
|z| ≥ 3Very rare, potential outlierOnly 0.3% of values

Rule of thumb: In a normal distribution, values beyond z = ±2 occur only about 5% of the time—this is why α = 0.05 is a common significance threshold.

Z-Scores and Probability

For normally distributed data, z-scores convert directly to probabilities using the standard normal distribution (mean = 0, SD = 1). This allows you to answer questions like "What percentage of people score above this value?" or "What score is at the 90th percentile?"

Z-ScoreArea Below (Left)Area Above (Right)Two-Tailed Area
z = 1.0084.13%15.87%31.74%
z = 1.6595.05%4.95%9.90%
z = 1.9697.50%2.50%5.00%
z = 2.0097.72%2.28%4.56%
z = 2.5899.51%0.49%0.99%
z = 3.0099.87%0.13%0.27%

Critical values: z = 1.96 for 95% confidence (5% in tails); z = 2.576 for 99% confidence (1% in tails).

Z-Scores for Sample Means

When working with sample means rather than individual values, use the standard error (SE = σ/√n) instead of the standard deviation. This accounts for the fact that sample means are less variable than individual values.

ContextFormulaUse Case
Individual valuez = (x - μ) / σHow unusual is this one value?
Sample meanz = (x̄ - μ) / (σ/√n)How unusual is this sample mean?
Proportionz = (p̂ - p) / √[p(1-p)/n]How unusual is this sample proportion?

Z-Score for Sample Mean

z = (x̄ - μ) / (σ / √n) = (x̄ - μ) / SE

Where:

  • = Sample mean
  • μ= Population mean (hypothesized)
  • σ= Population standard deviation
  • n= Sample size
  • SE= Standard error = σ/√n

Standardization: Comparing Different Scales

Z-scores allow you to compare values from different distributions by converting everything to a common scale (mean = 0, SD = 1). This is powerful for comparing performance across different tests or metrics.

TestRaw ScoreMeanSDZ-ScorePercentile
SAT12001050200z = 0.7577%
ACT28215z = 1.4092%
IQ11510015z = 1.0084%
GRE Quant1651537.5z = 1.6095%

In this example, the ACT score (z = 1.40) is relatively better than the SAT score (z = 0.75), even though both are above average.

Z-Scores in Confidence Intervals

Z-scores define the critical values for confidence intervals when the population standard deviation is known (or for large samples where we use t-distribution instead).

Confidence Levelα (Two-Tailed)Z-Critical (z*)Interval Formula
90%0.10±1.645x̄ ± 1.645 × SE
95%0.05±1.960x̄ ± 1.960 × SE
99%0.01±2.576x̄ ± 2.576 × SE

Interpretation: A 95% confidence interval means that if you repeated the sampling process many times, about 95% of the intervals would contain the true population parameter.

Applications of Z-Scores

Z-scores are used throughout statistics, research, and everyday applications. They standardize data for comparison and enable probability calculations.

FieldApplicationHow Z-Scores Help
EducationTest score comparisonCompare SAT vs ACT performance
FinanceRisk assessmentStock returns relative to market
Quality ControlProcess monitoringDetect out-of-control processes (z > 3)
MedicineGrowth chartsChild height/weight percentiles
ResearchHypothesis testingCalculate p-values for significance
SportsPerformance comparisonCompare athletes across different eras

Worked Examples

Finding a Z-Score

Problem:

A student scores 78 on a test where the mean is 70 and the standard deviation is 8. What is their z-score?

Solution Steps:

  1. 1Identify values: x = 78, μ = 70, σ = 8
  2. 2Apply z-score formula: z = (x - μ) / σ
  3. 3Calculate: z = (78 - 70) / 8 = 8 / 8 = 1.00

Result:

Z-score = 1.00. The student scored exactly 1 standard deviation above the mean, placing them at approximately the 84th percentile.

Finding Value from Z-Score

Problem:

IQ scores have mean 100 and SD 15. What IQ score corresponds to the 95th percentile (z = 1.645)?

Solution Steps:

  1. 1Rearrange z-score formula: x = μ + z × σ
  2. 2Identify values: μ = 100, σ = 15, z = 1.645
  3. 3Calculate: x = 100 + 1.645 × 15 = 100 + 24.68 = 124.68

Result:

An IQ of 125 (rounded) is at the 95th percentile. Only 5% of people score higher.

Z-Score for Sample Mean

Problem:

A population has mean 500 and SD 100. A sample of 25 people has mean 525. How unusual is this sample?

Solution Steps:

  1. 1Calculate standard error: SE = σ/√n = 100/√25 = 100/5 = 20
  2. 2Calculate z-score: z = (x̄ - μ) / SE = (525 - 500) / 20 = 1.25
  3. 3Find probability: P(z > 1.25) = 1 - 0.8944 = 0.1056

Result:

Z = 1.25, p-value ≈ 0.106 (one-tailed). About 10.6% of samples would have means this high or higher by chance—not statistically unusual.

Tips & Best Practices

  • Remember: z = (value - mean) / SD. Positive z means above average; negative means below.
  • For 95% confidence intervals, use z = ±1.96; for 99%, use z = ±2.576.
  • Values beyond z = ±2 are unusual (only ~5% of data); beyond z = ±3 are very rare (~0.3%).
  • When comparing different tests, convert to z-scores first—they put everything on the same scale.
  • For sample means, use standard error (SD/√n) instead of SD in the z-score formula.
  • Z-scores are dimensionless—they have no units, which makes them universally comparable.
  • The empirical rule (68-95-99.7) gives quick approximations for z = ±1, ±2, ±3.

Frequently Asked Questions

Yes! Negative z-scores indicate values below the mean. A z-score of -2 means the value is 2 standard deviations below average. In a normal distribution, half the values have negative z-scores (the below-average half).
It depends on context. For test scores, z > 1 is above average; z > 2 is excellent (top 2.5%). For statistical significance, |z| > 1.96 is significant at α = 0.05 level. For quality control, |z| < 3 is acceptable; beyond that may indicate a problem.
Use z-scores when: (1) population standard deviation is known, or (2) sample size is large (n > 30). Use t-scores when: (1) population SD is unknown and (2) sample is small. T-distributions are wider than normal, accounting for extra uncertainty from estimating σ.
Z-scores can be calculated for any distribution—they simply measure 'how many SDs from the mean.' However, converting z-scores to percentiles/probabilities using the standard normal table only works for normally distributed data (or large samples via Central Limit Theorem).
For normal distributions: z = 0 → 50th percentile; z = 1 → 84th; z = 2 → 98th; z = -1 → 16th. Use a z-table to convert between them. Each z-score maps to a specific area under the normal curve, which equals the percentile.
Z = ±1.96 captures the middle 95% of a normal distribution, leaving 2.5% in each tail. This makes it the critical value for 95% confidence intervals and the boundary for statistical significance at the α = 0.05 level—the most common threshold in research.

Sources & References

Last updated: 2026-01-22