Acceleration Calculator

Calculate acceleration, velocity, time, or distance using the kinematic equations. Convert between metric and imperial units.

Input Values

Unit System:

Solve For:

0 m/s
0 m/s100 m/s
m/s
20 m/s
0 m/s100 m/s
m/s
5 s
0.1 s60 s
s

Acceleration

4.0000 m/s²

G-force: 0.408g

🚀Acceleration
4.0000 m/s²
💪G-Force
0.408g
💨Final Velocity
20.00 m/s
📏Distance
50.00 m

At This Acceleration:

0-60 mph time

24.14s

0-100 km/h time

25.00s

Formulas Used:

a = (v - v₀) / t

d = v₀t + ½at²

v² = v₀² + 2ad

Common Accelerations

Human walking

0.5 m/s²

Car (normal)

2-4 m/s²

Sports car

5-8 m/s²

Gravity (Earth)

9.81 m/s²

Fighter jet

30-90 m/s²

Space shuttle

29 m/s²

Understanding Acceleration

Acceleration is the rate of change of velocity. It tells us how quickly an object is speeding up or slowing down. A positive acceleration means the object is speeding up, while a negative acceleration (deceleration) means it's slowing down. The SI unit is meters per second squared (m/s²).

What is Acceleration?

Acceleration is the rate of change of velocity with respect to time. It's a vector quantity, meaning it has both magnitude and direction, and is fundamental to understanding motion in physics.

ConceptSymbolSI UnitDescription
Accelerationam/s²Rate of velocity change
Velocityvm/sRate of position change
TimetsDuration of change
DisplacementΔxmChange in position

Basic Acceleration Formula

a = (v - v₀) / t = Δv / Δt

Where:

  • a= Acceleration (m/s²)
  • v= Final velocity (m/s)
  • v₀= Initial velocity (m/s)
  • t= Time elapsed (s)

Types of Acceleration

Acceleration can take various forms depending on how velocity changes:

TypeDescriptionExample
Positive AccelerationVelocity increasing in direction of motionCar speeding up
Negative Acceleration (Deceleration)Velocity decreasingCar braking
Centripetal AccelerationDirection change at constant speedCar turning a corner
Uniform AccelerationConstant rate of changeFree fall (ignoring air)
Non-uniform AccelerationVarying rate of changeRocket launch
Angular AccelerationRate of change of angular velocitySpinning wheel speeding up

Kinematic Equations for Constant Acceleration

When acceleration is constant, these four kinematic equations describe the motion:

EquationVariablesUse When
v = v₀ + atv, v₀, a, tNo displacement needed
x = v₀t + ½at²x, v₀, a, tNo final velocity needed
v² = v₀² + 2axv, v₀, a, xNo time needed
x = ½(v + v₀)tx, v, v₀, tNo acceleration needed

Strategy: Identify three known quantities and one unknown, then select the equation containing exactly those four variables.

Kinematic Equations

v = v₀ + at x = v₀t + ½at² v² = v₀² + 2ax x = ½(v + v₀)t

Where:

  • x= Displacement (m)
  • v₀= Initial velocity (m/s)
  • v= Final velocity (m/s)
  • a= Acceleration (m/s²)
  • t= Time (s)

Gravitational Acceleration

Gravitational acceleration (g) is the acceleration caused by gravity, varying by location:

Locationg ValueNotes
Earth (sea level)9.81 m/s²Standard value (often rounded to 10)
Earth (equator)9.78 m/s²Reduced by Earth's rotation
Earth (poles)9.83 m/s²No centrifugal effect
Moon1.62 m/s²About 1/6 of Earth's
Mars3.71 m/s²About 38% of Earth's
Jupiter24.79 m/s²About 2.5× Earth's

Free Fall Equations

v = v₀ + gt y = v₀t + ½gt² v² = v₀² + 2gy

Where:

  • g= Gravitational acceleration (9.81 m/s² on Earth)
  • y= Vertical displacement (m)
  • v₀= Initial velocity (m/s)

Centripetal Acceleration

Centripetal acceleration occurs when an object moves in a circular path, constantly changing direction even if speed remains constant.

QuantityFormulaUnit
Centripetal accelerationaᴄ = v²/r = ω²rm/s²
Centripetal forceFᴄ = mv²/r = mω²rN
Angular velocityω = v/r = 2πfrad/s
PeriodT = 2πr/v = 1/fs

Direction: Centripetal acceleration always points toward the center of the circular path, perpendicular to velocity.

Centripetal Acceleration

aᴄ = v²/r = ω²r = 4π²r/T²

Where:

  • aᴄ= Centripetal acceleration (m/s²)
  • v= Tangential velocity (m/s)
  • r= Radius of circular path (m)
  • ω= Angular velocity (rad/s)

Acceleration and Newton's Second Law

Newton's Second Law directly relates acceleration to force and mass:

RelationshipImplicationExample
F = maForce produces accelerationPushing a cart
a = F/mMore mass = less accelerationLoaded vs empty truck
ΣF = maNet force determines accelerationTug of war

Key insight: An object accelerates only when a net force acts on it. No net force means constant velocity (including zero).

Newton's Second Law

F = ma a = F/m ΣF = ma (for multiple forces)

Where:

  • F= Force (Newtons, N)
  • m= Mass (kg)
  • a= Acceleration (m/s²)

Real-World Applications

Acceleration calculations are essential in many fields:

ApplicationTypical ValuesConsiderations
Vehicle performance0-60 mph in 3-10 sMarketing specs, 0-100 km/h
Roller coastersUp to 6gHuman tolerance limits
Aircraft takeoff0.3-0.5gRunway length calculations
Braking systems0.8-1.0g maximumTire friction limits
Elevators1-1.5 m/s²Comfort considerations
Spacecraft launch3-4g sustainedAstronaut training required

Worked Examples

Car Acceleration from Rest

Problem:

A sports car accelerates from 0 to 100 km/h in 5 seconds. Calculate the acceleration.

Solution Steps:

  1. 1Convert units: 100 km/h = 100 × (1000/3600) = 27.78 m/s
  2. 2Apply formula: a = (v - v₀) / t
  3. 3Substitute: a = (27.78 - 0) / 5
  4. 4Calculate: a = 5.56 m/s²
  5. 5Express in g: 5.56 / 9.81 = 0.57g

Result:

Acceleration = 5.56 m/s² (0.57g)

Braking Distance

Problem:

A car traveling at 30 m/s brakes with deceleration of 8 m/s². Find the stopping distance.

Solution Steps:

  1. 1Given: v₀ = 30 m/s, v = 0, a = -8 m/s²
  2. 2Use: v² = v₀² + 2ax
  3. 3Solve for x: 0 = 30² + 2(-8)x
  4. 40 = 900 - 16x
  5. 5x = 900/16 = 56.25 m

Result:

Stopping distance = 56.25 meters

Centripetal Acceleration

Problem:

A car takes a curve of radius 50 m at 20 m/s. What is the centripetal acceleration?

Solution Steps:

  1. 1Use formula: aᴄ = v²/r
  2. 2Substitute: aᴄ = 20²/50
  3. 3Calculate: aᴄ = 400/50 = 8 m/s²
  4. 4Express in g: 8/9.81 = 0.82g

Result:

Centripetal acceleration = 8 m/s² (0.82g)

Tips & Best Practices

  • Always check units: acceleration should be in m/s², not m/s or m/s³
  • Draw a diagram with arrows showing positive direction before solving
  • When using kinematic equations, be consistent with signs for direction
  • For vertical motion, decide if up or down is positive and stick with it
  • Remember: zero velocity doesn't mean zero acceleration (ball at top of throw)
  • Convert km/h to m/s by multiplying by (1000/3600) = 0.278
  • Use v² = v₀² + 2ax when time isn't given or needed

Frequently Asked Questions

Speed measures how fast something is moving (m/s), while acceleration measures how fast the speed is changing (m/s²). A car can have high speed with zero acceleration (constant velocity) or zero speed with non-zero acceleration (the moment it starts moving). Acceleration is the rate of change of velocity, not velocity itself.
Yes! An object moving in a circle at constant speed has centripetal acceleration because its direction is constantly changing. Acceleration is the rate of change of velocity, which is a vector. Since velocity has both magnitude (speed) and direction, changing either one constitutes acceleration.
Negative acceleration means the acceleration vector points opposite to the positive direction you've defined. If positive is forward, negative acceleration could mean slowing down while moving forward (deceleration) OR speeding up while moving backward. The sign depends on your coordinate system choice, not inherently on speeding up or slowing down.
According to Newton's second law (F=ma) and the law of gravitation (F=GMm/r²), when you solve for acceleration, the mass m cancels out: a = GM/r². This means all objects at the same location experience the same gravitational acceleration regardless of their mass. Galileo demonstrated this famously (though not at the Leaning Tower of Pisa as legend claims).
A g-force expresses acceleration relative to Earth's gravity (1g = 9.81 m/s²). Humans can briefly tolerate 5-9g (trained pilots in special suits), but sustained high g-forces cause blood pooling, vision problems (graying/blackout), and loss of consciousness. Roller coasters typically stay under 4-5g, while astronauts experience about 3g during launch.
Follow this systematic approach: 1) Draw a diagram and establish a coordinate system, 2) List all known quantities with their signs, 3) Identify what you need to find, 4) Select the kinematic equation containing exactly the three known quantities plus your unknown, 5) Solve algebraically, then substitute numbers, 6) Check units and reasonableness. Most problems give you 3 quantities and ask for 1.

Sources & References

Last updated: 2026-01-22