Dilution Calculator

Calculate dilutions using the C1V1=C2V2 formula. Find initial or final concentration, volume needed for dilution, and dilution factor.

Dilution Parameters

Solve For:

Concentration Unit:

Volume Unit:

M
mL
mL

Quick Presets:

Final Concentration (C₂)

2.0000 M

Complete Solution:

C₁ (Initial Conc.)

10.0000 M

V₁ (Initial Vol.)

50.0000 mL

C₂ (Final Conc.)

2.0000 M

V₂ (Final Vol.)

250.0000 mL

🔬Dilution Factor
5.00×
⚗️Dilution Ratio
1:5.0
💧Solvent to Add
200.0000 mL
📊% Dilution
80.00%

How to Prepare:

  1. Take 50.0000 mL of stock solution (10.0000 M)
  2. Add 200.0000 mL of solvent
  3. Mix well to get 250.0000 mL of 2.0000 M solution

Formula Used:

C₁V₁ = C₂V₂

10.0000 × 50.0000 = 2.0000 × 250.0000

Serial Dilution Series

If you continue diluting at the same factor (5.00×):

StepConcentrationTotal Dilution
110.0000 M1:5.00
22.0000 M1:25.00
30.4000 M1:125.00
40.0800 M1:625.00
50.0160 M1:3125.00

Understanding Dilution

Dilution is the process of decreasing the concentration of a solution by adding more solvent. The C₁V₁=C₂V₂ formula is based on conservation of mass - the amount of solute stays the same before and after dilution, only the concentration changes. This formula assumes ideal behavior and is widely used in laboratory settings for preparing standard solutions.

What Is Dilution?

Dilution is the process of reducing the concentration of a solution by adding more solvent. The amount of solute (dissolved substance) stays constant—only the total volume changes. Dilution is fundamental to laboratory work, from preparing reagents to making serial dilutions for assays.

TermDefinitionExample
Stock solutionConcentrated starting solution12 M HCl, 10× buffer
Working solutionDiluted solution for use1 M HCl, 1× buffer
Dilution factorRatio of final to initial volume10× dilution: 1 mL stock + 9 mL solvent
DiluentSolvent used to diluteWater, buffer, saline

Dilution Equation

C₁V₁ = C₂V₂

Where:

  • C₁= Initial (stock) concentration
  • V₁= Volume of stock solution needed
  • C₂= Final (desired) concentration
  • V₂= Final total volume

Understanding Dilution Factor

The dilution factor describes how much a solution has been diluted. It can be expressed as a ratio, fold-dilution, or fraction.

ExpressionMeaningStock Needed for 100 mLConcentration Change
1:10 dilution1 part stock + 9 parts solvent10 mL + 90 mL10× less concentrated
1:100 dilution1 part stock + 99 parts solvent1 mL + 99 mL100× less concentrated
10-fold dilutionSame as 1:1010 mL + 90 mL10× less concentrated
1/5 dilutionFinal is 1/5 original conc.20 mL + 80 mL5× less concentrated

Key relationship: Dilution Factor = C₁/C₂ = V₂/V₁. A 10× dilution means the final concentration is 1/10th of the original.

Serial Dilutions

Serial dilution is a stepwise dilution where each step uses the previous dilution as stock. This is essential for creating a range of concentrations for calibration curves, dose-response studies, and bacterial counts.

StepDilution FactorCumulative DilutionIf Starting at 1 M
Original1 M
1st 1:1010×10×0.1 M (100 mM)
2nd 1:1010×100×0.01 M (10 mM)
3rd 1:1010×1,000×0.001 M (1 mM)
4th 1:1010×10,000×0.0001 M (100 μM)

Common serial dilutions: 1:2 (2-fold), 1:3 (3-fold), 1:10 (10-fold). Cumulative dilution = product of individual factors.

Proper Dilution Technique

Accurate dilution requires proper technique, especially for concentrated acids and bases.

Solution TypeTechniqueWhy
Concentrated acidsAlways add acid to waterWater splashing into acid causes violent boiling
Concentrated basesAdd base to water slowlyExothermic; can splash
Viscous solutionsRinse pipette tip with diluentEnsures complete transfer
Volatile solventsWork in fume hood; coverEvaporation changes concentration
Precise workUse volumetric glasswareBeakers/cylinders less accurate

Safety mnemonic: "Do as you oughta, add acid to water" or "AAA = Always Add Acid (to water)".

Dilution with Different Concentration Units

C₁V₁ = C₂V₂ works with any concentration unit as long as both concentrations use the same unit.

Unit TypeExample CalculationNotes
Molarity (M)6 M × 10 mL = 1 M × V₂Most common in chemistry
Percent (%)70% × V₁ = 10% × 100 mLCommercial reagents
mg/mL50 mg/mL × V₁ = 5 mg/mL × 10 mLProtein solutions
Fold (×)10× × V₁ = 1× × 50 mLBuffers, media
Parts per million1000 ppm × V₁ = 100 ppm × V₂Trace analysis

Volume units: Must also match (both in mL, both in L, etc.) or be converted.

Common Laboratory Dilutions

Many standard dilutions are used repeatedly in laboratories. Here are frequently needed calculations.

ApplicationStockFinalPreparation (per 100 mL)
HCl working solution12 M (conc.)1 M8.3 mL stock + 91.7 mL H₂O
10× PBS to 1×10× PBS1× PBS10 mL stock + 90 mL H₂O
Ethanol dilution95%70%73.7 mL stock + 26.3 mL H₂O
Bleach sanitizer5.25%0.5%9.5 mL stock + 90.5 mL H₂O
NaOH working10 M0.1 M1 mL stock + 99 mL H₂O

Applications of Dilution

Dilution is used throughout science, medicine, and industry for various purposes.

FieldApplicationExample
Analytical ChemistryCalibration standardsSerial dilutions for standard curves
MicrobiologyViable cell counts10-fold serial dilutions for plating
PharmacyMedication preparationDiluting IV drugs to correct dose
EnvironmentalSample analysisDiluting samples into detector range
Food IndustryFlavor/additive adjustmentConcentrate to ready-to-drink
ResearchDose-response curvesDrug concentration series

Worked Examples

Basic Dilution Calculation

Problem:

How do you prepare 500 mL of 0.5 M NaCl from a 5 M stock solution?

Solution Steps:

  1. 1Identify knowns: C₁ = 5 M, C₂ = 0.5 M, V₂ = 500 mL
  2. 2Apply C₁V₁ = C₂V₂: 5 M × V₁ = 0.5 M × 500 mL
  3. 3Solve for V₁: V₁ = (0.5 × 500) / 5 = 250 / 5 = 50 mL
  4. 4Dilution factor check: 5/0.5 = 10× dilution ✓

Result:

Add 50 mL of 5 M NaCl stock to enough water to make 500 mL total volume. This is a 10-fold dilution (add 50 mL stock + 450 mL water).

Preparing Working Acid Solution

Problem:

Prepare 250 mL of 2 M H₂SO₄ from concentrated H₂SO₄ (18 M).

Solution Steps:

  1. 1C₁ = 18 M, C₂ = 2 M, V₂ = 250 mL
  2. 2V₁ = (C₂ × V₂) / C₁ = (2 × 250) / 18 = 27.8 mL
  3. 3Safety: NEVER add water to concentrated acid!
  4. 4Procedure: Add ~150 mL water to flask first, slowly add 27.8 mL conc. H₂SO₄ while swirling, cool, then dilute to 250 mL mark

Result:

Use 27.8 mL of 18 M H₂SO₄. Always add acid to water to prevent violent boiling. Allow solution to cool before bringing to final volume.

Serial Dilution for Bacterial Count

Problem:

Create a 6-step 10-fold serial dilution from a bacterial culture for colony counting.

Solution Steps:

  1. 1Label tubes 10⁻¹ through 10⁻⁶
  2. 2Add 9 mL sterile diluent to each tube
  3. 3Transfer 1 mL from original culture to tube 10⁻¹ (1:10 dilution)
  4. 4Mix well, transfer 1 mL from 10⁻¹ to 10⁻², repeat to 10⁻⁶
  5. 5Each step: 1 mL sample + 9 mL diluent = 10 mL total
  6. 6Final dilution: 10⁻⁶ (1 million-fold)

Result:

Serial dilution complete. If 150 colonies grow from 0.1 mL of the 10⁻⁵ dilution: CFU/mL = 150 × 10 × 10⁵ = 1.5 × 10⁸ bacteria/mL in original.

Tips & Best Practices

  • Always add acid to water (AAA), never water to acid—prevents violent exothermic reactions.
  • Use the dilution factor to verify your calculation: C₁/C₂ should equal V₂/V₁.
  • For precise work, add stock to partial diluent, mix, then bring to final volume in a volumetric flask.
  • C₁V₁ = C₂V₂ only works when solute amount doesn't change—no reactions, no precipitation.
  • Serial dilutions improve accuracy for large dilution factors (>100×).
  • Label all dilutions clearly with concentration, date, and preparer.
  • Account for thermal expansion if diluting solutions with significant heat of mixing.

Frequently Asked Questions

1:10 usually means 1 part sample + 9 parts diluent = 10 parts total (10× dilution). 1/10 means final concentration is 1/10 of original—same thing. However, some fields use 1:10 to mean 1 part to 10 parts (11 total, ~11× dilution). Always clarify notation in protocols.
When water contacts concentrated acid, the dilution is highly exothermic (releases heat). A small amount of water added to acid can instantly boil and violently splash concentrated acid. Adding acid to water disperses the heat through a larger volume, preventing localized boiling and dangerous splashing.
Yes, as long as both C₁ and C₂ use the same unit (both in M, both in %, both in mg/mL, etc.) and both V₁ and V₂ use the same unit. The equation expresses conservation of solute amount: amount before = amount after.
Diluent volume = Final volume - Stock volume = V₂ - V₁. If you need V₁ = 50 mL stock to make V₂ = 500 mL final, add 450 mL of diluent. However, for precise work, add stock to some diluent, mix, then bring to final volume (accounts for volume changes on mixing).
You can't create a more concentrated solution by dilution—you can only dilute. If C₁ < C₂, you'd get a negative V₁, which is physically impossible. You need to either get a more concentrated stock or evaporate/concentrate your existing solution.
Serial dilutions are more accurate for large dilution factors. Pipetting 0.001 mL directly is imprecise and impractical. Instead, three consecutive 1:10 dilutions (each 1 mL into 9 mL) achieves 1:1000 with much better accuracy using reasonable volumes.

Sources & References

Last updated: 2026-01-22