Ka Kb Calculator

Calculate acid and base dissociation constants (Ka, Kb) from experimental data

Ka and Kb Calculations

Ka

1.8446e-5

pKa

4.7341

Kb

5.4213e-10

pKb

9.2659

Percent Ionization

1.35%

Formulas:

Ka = [H+][A-] / [HA]

Kb = [BH+][OH-] / [B]

Ka x Kb = Kw = 10^-14

Understanding Ka and Kb

Ka (acid dissociation constant) and Kb (base dissociation constant) quantify the strength of weak acids and bases. Larger Ka values indicate stronger acids, while larger Kb values indicate stronger bases. These constants can be determined experimentally by measuring the pH of a solution with known concentration.

What Are Ka and Kb?

Ka (acid dissociation constant) and Kb (base dissociation constant) quantify the strength of weak acids and weak bases in aqueous solution. Ka measures how readily a weak acid donates a proton to water, while Kb measures how readily a weak base accepts a proton from water. Unlike strong acids and bases that dissociate completely, weak acids and bases exist in equilibrium, and Ka and Kb describe the position of that equilibrium.

For a weak acid HA dissociating in water, the equilibrium expression is HA ⇌ H⁺ + A⁻, with Ka = [H⁺][A⁻]/[HA]. A larger Ka means the acid dissociates more completely and is therefore stronger. For example, acetic acid has Ka = 1.8 × 10⁻⁵, meaning only about 0.4% of molecules donate a proton in a 0.1 M solution. Strong acids like HCl have Ka values so large that they effectively dissociate completely.

The relationship between Ka and Kb for a conjugate acid-base pair is Ka × Kb = Kw = 10⁻¹⁴ at 25°C. This means that a stronger acid (larger Ka) has a weaker conjugate base (smaller Kb), and vice versa. For example, the Ka of acetic acid is 1.8 × 10⁻⁵, so the Kb of its conjugate base (acetate) is 10⁻¹⁴/1.8 × 10⁻⁵ = 5.6 × 10⁻¹⁰.

This calculator supports four calculation modes: Ka from pH, Kb from pOH, pH from Ka, and pOH from Kb. It also calculates percent ionization and provides all related equilibrium constants (Ka, Kb, pKa, pKb, pH, pOH) for complete characterization of the acid-base system.

Acid-Base Equilibrium Formulas

The fundamental relationships between Ka, Kb, pH, pOH, and the autoionization constant of water.

Acid-Base Equilibrium

Ka = [H⁺][A⁻]/[HA]; Kb = [BH⁺][OH⁻]/[B]; Ka × Kb = Kw = 10⁻¹⁴

Where:

  • Ka= Acid dissociation constant (dimensionless)
  • Kb= Base dissociation constant (dimensionless)
  • pKa= Negative log of Ka: pKa = -log₁₀(Ka)
  • pKb= Negative log of Kb: pKb = -log₁₀(Kb)
  • Kw= Autoionization constant of water = 10⁻¹⁴ at 25°C

How to Use This Calculator

Follow these steps to calculate acid-base equilibrium constants:

  1. Select Calculation Mode: Choose one of four modes:
    • Ka from pH: Calculate Ka when you know the pH and concentration of a weak acid solution.
    • Kb from pOH: Calculate Kb when you know the pOH and concentration of a weak base solution.
    • pH from Ka: Calculate the pH when you know Ka and the initial acid concentration.
    • pOH from Kb: Calculate the pOH when you know Kb and the initial base concentration.
  2. Enter the Values: Input the known quantities in the fields provided. For Ka from pH mode, enter the initial concentration (M) and the measured pH. For pH from Ka mode, enter the Ka value and the initial concentration.
  3. View Results: The calculator displays Ka, pKa, Kb, pKb, pH, pOH, [H⁺] or [OH⁻], and percent ionization. All related equilibrium constants are shown for complete characterization.

Understanding the Results

The results provide a complete description of the acid-base equilibrium:

Ka and pKa: The acid dissociation constant and its negative logarithm. Larger Ka (smaller pKa) means a stronger acid. For reference: HCl (strong), pKa ≈ -7; acetic acid, pKa = 4.74; water, pKa = 15.74. The pKa scale is more convenient because it compresses the wide range of Ka values into a manageable range.

Kb and pKb: The base dissociation constant and its negative logarithm. Larger Kb (smaller pKb) means a stronger base. The relationship Ka × Kb = Kw ensures that if you know one, you can calculate the other for any conjugate pair.

pH and pOH: The negative logarithms of hydrogen ion and hydroxide ion concentrations. At 25°C, pH + pOH = 14. The pH tells you whether the solution is acidic (pH < 7), neutral (pH = 7), or basic (pH > 7).

Percent Ionization: The fraction of the weak acid or base that has dissociated. For weak acids, percent ionization = [H⁺]₀/[HA]₀ × 100%. Stronger acids and more dilute solutions have higher percent ionization. For example, 0.1 M acetic acid has about 1.3% ionization, while 0.01 M acetic acid has about 4.2%.

Real-World Applications

Buffer systems in biology and medicine depend on Ka and Kb values. Blood maintains a pH of 7.35-7.45 using the carbonic acid/bicarbonate buffer system (pKa = 6.10). When the pH matches the pKa, the buffer has maximum capacity to resist pH changes. Understanding Ka and Kb is essential for designing buffer solutions for biochemical experiments and pharmaceutical formulations.

Environmental chemistry uses Ka values to predict the behavior of pollutants in water. The speciation of weak acids like hydrofluoric acid (HF, pKa = 3.17) and hydrogen cyanide (HCN, pKa = 9.21) depends on pH. At pH values below the pKa, the protonated (molecular) form dominates, which may be more toxic or more mobile in groundwater.

Food science relies on Ka values for flavor, preservation, and fermentation. Lactic acid (pKa = 3.86) and acetic acid (pKa = 4.74) are produced during fermentation and contribute to the tangy flavors of yogurt, sauerkraut, and vinegar. The pH of food products affects microbial growth, enzyme activity, and shelf life.

Pharmaceutical chemistry uses pKa values to optimize drug absorption and distribution. The ionization state of a drug molecule determines its solubility, membrane permeability, and protein binding. Drugs with pKa values near physiological pH (7.4) have pH-dependent absorption, which affects dosing strategies.

Worked Examples

Ka from pH

Problem:

A 0.1 M acetic acid solution has pH = 2.87. Calculate Ka.

Solution Steps:

  1. 1From pH = 2.87: [H⁺] = 10⁻²·⁸⁷ = 1.35 × 10⁻³ M
  2. 2At equilibrium: [H⁺] = [A⁻] = 1.35 × 10⁻³ M
  3. 3[HA] = 0.1 - 1.35 × 10⁻³ = 0.09865 M
  4. 4Ka = [H⁺][A⁻]/[HA] = (1.35 × 10⁻³)² / 0.09865 = 1.85 × 10⁻⁵
  5. 5pKa = -log(1.85 × 10⁻⁵) = 4.73

Result:

Ka = 1.85 × 10⁻⁵ (pKa = 4.73), consistent with the known value for acetic acid.

pH from Ka

Problem:

Calculate the pH of 0.1 M acetic acid (Ka = 1.8 × 10⁻⁵).

Solution Steps:

  1. 1Set up equilibrium: Ka = x²/(C - x), where x = [H⁺]
  2. 2Assume x << C: Ka ≈ x²/C → x = √(Ka × C)
  3. 3x = √(1.8 × 10⁻⁵ × 0.1) = √(1.8 × 10⁻⁶) = 1.34 × 10⁻³ M
  4. 4pH = -log(1.34 × 10⁻³) = 2.87
  5. 5Percent ionization = (1.34 × 10⁻³ / 0.1) × 100% = 1.34%

Result:

The pH of 0.1 M acetic acid is 2.87 with 1.34% ionization.

Conjugate Base Kb

Problem:

Calculate the Kb of the acetate ion (CH₃COO⁻) given that acetic acid has Ka = 1.8 × 10⁻⁵.

Solution Steps:

  1. 1Use the relationship: Ka × Kb = Kw = 10⁻¹⁴
  2. 2Kb = Kw / Ka = 10⁻¹⁴ / 1.8 × 10⁻⁵
  3. 3Kb = 5.56 × 10⁻¹⁰
  4. 4pKb = -log(5.56 × 10⁻¹⁰) = 9.26
  5. 5Check: pKa + pKb = 4.74 + 9.26 = 14.00 ✓

Result:

The Kb of acetate is 5.56 × 10⁻¹⁰ (pKb = 9.26), confirming it is a very weak base.

Tips & Best Practices

  • Use the pKa scale for easier comparison: lower pKa = stronger acid.
  • At 25°C, pKa + pKb = 14 for any conjugate acid-base pair.
  • Maximum buffer capacity occurs when pH = pKa.
  • Percent ionization increases as concentration decreases for weak acids and bases.
  • Ka values are temperature-dependent — always specify the temperature.
  • For polyprotic acids, each dissociation step has its own Ka₁, Ka₂, Ka₃.

Frequently Asked Questions

Ka is the acid dissociation constant on a linear scale, while pKa is its negative logarithm (pKa = -log Ka). The pKa scale compresses the very wide range of Ka values (from 10¹⁵ for strong acids to 10⁻⁵⁰ for very weak acids) into a more manageable range. Lower pKa means stronger acid. A difference of 1 in pKa corresponds to a 10-fold difference in acid strength.
For any conjugate acid-base pair, Ka × Kb = Kw = 10⁻¹⁴ at 25°C. This means a strong acid (large Ka) has a weak conjugate base (small Kb), and vice versa. For example, HCl (strong acid) has Cl⁻ as its conjugate base, which is negligibly weak (extremely small Kb). This relationship is fundamental to buffer chemistry and acid-base equilibrium.
Percent ionization is the fraction of the initial acid or base concentration that has dissociated into ions. For weak acids, it equals [H⁺]₀/[HA]₀ × 100%. It differs from dissociation in that ionization refers specifically to the formation of ions in solution. For most practical purposes in acid-base chemistry, these terms are used interchangeably.
Ka is an equilibrium constant and does not change with concentration at a given temperature. However, the degree of dissociation (percent ionization) does change with concentration. Dilute solutions have higher percent ionization because the equilibrium shifts to produce more ions. This is an application of Le Chatelier's principle to the dissociation equilibrium.
This relationship arises from the autoionization of water. When an acid HA donates a proton to water (HA + H₂O ⇌ H₃O⁺ + A⁻), and the conjugate base A⁻ accepts a proton from water (A⁻ + H₂O ⇌ HA + OH⁻), the product of the two equilibrium expressions gives [H₃O⁺][OH⁻] = Kw. This thermodynamic relationship connects all acid-base equilibria in water.

Sources & References

Last updated: 2026-06-06

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Editorial Note

MyCalcBuddy Editorial Team

This page is maintained as an educational calculator reference.

Source

Formula Source: Chemistry: The Central Science

by Brown, LeMay, Bursten

UpdatedLast reviewed: May 2026
CheckedFormula checks are based on standard references and internal QA review.