Electron Affinity Calculator
Compare electron affinities of elements in kJ/mol and eV. Predict anion formation tendency.
Compare Elements
Halogens (Highest EA):
Higher Electron Affinity
Cl
Difference: 21.0 kJ/mol
Cl
Exothermic
Anion: Favorable
F
Exothermic
Anion: Favorable
Understanding Electron Affinity
Electron affinity (EA) is the energy change when an electron is added to a neutral atom in the gas phase. A positive EA means energy is released (exothermic) when an electron is gained. Halogens have the highest electron affinities because gaining one electron completes their octet.
Noble Gases
EA = 0 (full valence shell)
Nitrogen Anomaly
Negative EA due to half-filled p orbitals
What Is Electron Affinity?
Electron affinity (EA) is the energy change that occurs when an electron is added to a neutral atom in the gas phase to form a negative ion (anion). It is one of the fundamental periodic properties, alongside ionization energy, electronegativity, and atomic radius. Understanding electron affinity helps predict how elements interact in chemical reactions, especially when forming ionic and polar covalent bonds.
A positive electron affinity means energy is released when the atom gains an electron, making the process exothermic and thermodynamically favorable. A negative electron affinity (or zero) indicates that the atom resists gaining an electron, meaning energy must be supplied to force the addition. Noble gases, for example, have electron affinities near zero because their valence shells are already full, leaving no stable configuration for an additional electron.
Electron affinity values vary across the periodic table in predictable trends. Halogens have the highest electron affinities because adding one electron completes their octet, producing a stable noble-gas configuration. Chlorine holds the record among naturally abundant elements at 349 kJ/mol, even surpassing fluorine (328 kJ/mol) due to fluorine's small atomic radius causing significant electron-electron repulsion. Elements with half-filled or fully filled subshells (like nitrogen and beryllium) often have low or negative electron affinities because the additional electron must enter a higher-energy orbital or face repulsion from the symmetric electron distribution.
Electron Affinity
Where:
- EA= Electron affinity (kJ/mol or eV)
- X(g)= Neutral atom in the gas phase
- X⁻(g)= Anion formed after gaining an electron
Periodic Trends in Electron Affinity
Electron affinity follows distinct patterns across the periodic table, driven by atomic structure and effective nuclear charge. Across a period from left to right, electron affinity generally increases because atoms become smaller and the nucleus exerts a stronger pull on incoming electrons. However, notable exceptions appear at elements with filled or half-filled subshells.
Down a group, electron affinity generally decreases because the added electron enters a shell farther from the nucleus, experiencing more shielding. This trend is most pronounced in the halogen group: fluorine (328 kJ/mol), chlorine (349 kJ/mol), bromine (324.6 kJ/mol), and iodine (295.2 kJ/mol). Interestingly, chlorine exceeds fluorine despite being below it, because fluorine's tiny atomic radius forces the extra electron very close to the existing electrons, causing repulsion that partially offsets the nuclear attraction.
The calculator converts between kilojoules per mole (kJ/mol) and electron volts (eV) using the conversion factor 1 eV = 96.485 kJ/mol. This dual-unit display is useful because kJ/mol is standard in thermochemistry while eV is common in atomic physics and computational chemistry. Comparing two elements side by side reveals which atom more readily accepts an electron and whether the anion formation is exothermic (favorable) or endothermic (unfavorable).
How to Use This Calculator
This calculator lets you compare the electron affinities of any two elements from its built-in database, displaying values in both kJ/mol and eV along with anion formation predictions.
- Select the first element: Choose from the dropdown menu. Common selections include halogens, chalcogens, and representative metals.
- Select the second element: Choose a second element to compare. The calculator highlights which element has the higher electron affinity.
- Quick-select halogens: Use the shortcut buttons (F, Cl, Br, I) for rapid comparison of the halogen series, which spans the highest electron affinities on the periodic table.
- Review the results: The display shows each element's EA in kJ/mol and eV, whether the electron addition is exothermic or endothermic, the predicted tendency to form an anion (Favorable, Possible, or Unlikely), and the absolute difference between the two values.
The anion formation tendency is classified as Favorable for EA above 50 kJ/mol, Possible for EA between 0 and 50 kJ/mol, and Unlikely for EA at or below zero. This heuristic helps predict whether an element will form stable anions in ionic compounds.
Understanding the Results
The results panel presents several key outputs. The higher electron affinity badge identifies which element more strongly attracts an additional electron. This element is more likely to form stable anions in chemical reactions and plays the role of the electron acceptor in ionic bonding.
The exothermic/endothermic indicators show whether energy is released or absorbed when the atom gains an electron. Exothermic processes (green indicators) are thermodynamically favorable and occur spontaneously. Endothermic processes (red indicators) require energy input and typically only proceed under specific conditions or when coupled with highly favorable reactions.
The anion formation tendency provides a practical assessment: elements with EA above 50 kJ/mol readily form anions (like halogens in salts), those between 0 and 50 kJ/mol may form anions under certain conditions, and those with zero or negative EA (like noble gases and alkaline earth metals) essentially never form stable anions.
The EA in eV values are useful for computational chemistry, photoelectron spectroscopy, and solid-state physics calculations where electron volts are the natural energy unit. The conversion uses the exact relationship 1 eV = 96.485 kJ/mol.
Real-World Applications
Electron affinity values are critical in several areas of chemistry and materials science. In ionic compound formation, the combination of ionization energy (energy to remove an electron) and electron affinity (energy released when an electron is gained) determines whether an ionic bond will form. A large positive EA combined with a low ionization energy makes ionic bonding highly favorable, as seen in sodium chloride where Na loses an electron and Cl gains one.
In semiconductor engineering, electron affinity determines the alignment of energy bands at interfaces between different materials. The electron affinity of silicon (approximately 4.05 eV) is a key parameter in designing MOSFET transistors, solar cells, and LED devices. Band offset calculations at heterojunctions depend directly on the difference in electron affinities of the two materials.
In computational chemistry and density functional theory (DFT), electron affinity is a benchmark property used to validate theoretical methods. Accurate prediction of EA values tests how well a computational approach handles electron correlation and exchange effects. High-level calculations aim to reproduce experimental EA values to within 0.01 eV.
Environmental chemistry also relies on electron affinity when modeling how pollutants like halogenated organic compounds behave in the atmosphere. The electron affinities of chlorine and fluorine atoms influence the reactivity and persistence of chlorofluorocarbons (CFCs) and related substances in stratospheric chemistry.
Worked Examples
Comparing Chlorine and Fluorine
Problem:
Compare the electron affinities of Cl (349 kJ/mol) and F (328 kJ/mol). Which element more readily forms an anion?
Solution Steps:
- 1Look up EA values: Cl = 349 kJ/mol, F = 328 kJ/mol
- 2Convert to eV: Cl = 349 / 96.485 = 3.617 eV, F = 328 / 96.485 = 3.400 eV
- 3Calculate difference: |349 − 328| = 21 kJ/mol
- 4Chlorine has the higher EA, so Cl more readily accepts an electron
Result:
Chlorine has the higher electron affinity (349 kJ/mol = 3.617 eV vs. fluorine's 328 kJ/mol = 3.400 eV). Both are exothermic and favorable for anion formation.
Noble Gas vs. Halogen
Problem:
Compare the electron affinities of Ne (0 kJ/mol) and Br (324.6 kJ/mol). Why is one zero?
Solution Steps:
- 1Neon: EA = 0 kJ/mol (noble gas, full valence shell)
- 2Bromine: EA = 324.6 kJ/mol = 3.365 eV
- 3Neon's complete 2p⁶ shell leaves no room for an additional electron in a low-energy orbital
- 4Bromine needs one electron to complete its 4p⁵ configuration to 4p⁶
Result:
Neon's EA is 0 because its full valence shell prevents stable anion formation. Bromine's EA is 324.6 kJ/mol (exothermic), making anion formation highly favorable.
Nitrogen Anomaly
Problem:
Why does nitrogen (Z = 7) have a negative or near-zero electron affinity despite being in Group 15?
Solution Steps:
- 1Nitrogen has the configuration 1s² 2s² 2p³ with a half-filled 2p subshell
- 2The half-filled subshell is exceptionally stable due to exchange energy stabilization
- 3Adding an electron forces pairing in one of the 2p orbitals, introducing electron-electron repulsion
- 4This repulsion outweighs the nuclear attraction, making EA ≈ −7 kJ/mol (endothermic)
Result:
Nitrogen has EA ≈ −7 kJ/mol because its half-filled 2p³ configuration is unusually stable. Adding an electron disrupts this symmetry and introduces repulsion, making the process endothermic.
Tips & Best Practices
- ✓Halogens consistently have the highest electron affinities due to their near-complete valence shells.
- ✓Chlorine exceeds fluorine in EA because fluorine's small radius causes electron-electron repulsion.
- ✓Noble gases have EA = 0 because their full valence shells cannot stabilize an additional electron.
- ✓Use the eV conversion (1 eV = 96.485 kJ/mol) when working with computational chemistry or spectroscopy data.
- ✓High EA combined with low ionization energy strongly favors ionic bond formation.
- ✓Elements with half-filled or fully filled subshells often show anomalously low or negative electron affinities.
Frequently Asked Questions
Sources & References
Last updated: 2026-06-06
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Editorial Note
MyCalcBuddy Editorial Team
This page is maintained as an educational calculator reference.
Formula Source: Chemistry: The Central Science
by Brown, LeMay, Bursten