Gibbs Free Energy Calculator
Calculate Gibbs free energy change (ΔG = ΔH - TΔS)
What Is Gibbs Free Energy?
Gibbs free energy (ΔG) is a thermodynamic quantity that determines whether a chemical process will occur spontaneously at constant temperature and pressure. Named after Josiah Willard Gibbs, it combines the effects of enthalpy (total heat content) and entropy (disorder) into a single criterion for spontaneity. A process is spontaneous when ΔG is negative, non-spontaneous when ΔG is positive, and at equilibrium when ΔG is zero.
The Gibbs free energy equation is ΔG = ΔH − TΔS, where ΔH is the enthalpy change, T is the absolute temperature in Kelvin, and ΔS is the entropy change. The enthalpy term represents the heat absorbed or released, while the TΔS term represents the energy associated with the increase in disorder. At low temperatures, enthalpy dominates, and exothermic reactions tend to be spontaneous. At high temperatures, entropy dominates, and reactions that increase disorder become more favorable.
The Gibbs free energy is directly related to the maximum non-expansion work a system can perform. In electrochemistry, ΔG = −nFEcell, connecting thermodynamics to measured cell potentials. The equilibrium constant is also related to ΔG through the equation ΔG° = −RT ln K, linking free energy to chemical equilibrium.
This calculator computes ΔG from enthalpy, entropy, and temperature inputs. It displays the result in kJ/mol, classifies the process as spontaneous or non-spontaneous, and shows the complete calculation chain for verification.
The Gibbs Free Energy Equation
The fundamental equation relates three thermodynamic quantities that together determine the direction and extent of a chemical process.
Gibbs Free Energy Equation
Where:
- ΔG= Gibbs free energy change (kJ/mol)
- ΔH= Enthalpy change (kJ/mol)
- T= Absolute temperature (Kelvin)
- ΔS= Entropy change (J/mol·K)
How to Use This Calculator
Follow these steps to calculate the Gibbs free energy change for any process:
- Enter Enthalpy Change (ΔH): Input the enthalpy change in kJ/mol. Negative values indicate exothermic processes (heat released), positive values indicate endothermic processes (heat absorbed).
- Enter Entropy Change (ΔS): Input the entropy change in J/mol·K. The calculator automatically converts this to kJ/mol·K by dividing by 1000. Positive values indicate increased disorder.
- Enter Temperature: Input the temperature in °C. The calculator converts it to Kelvin (T_K = T_C + 273.15) for the calculation.
- View Results: The calculator displays ΔG in kJ/mol and classifies the process as spontaneous (ΔG < 0), non-spontaneous (ΔG > 0), or at equilibrium (ΔG = 0).
The complete formula breakdown shows the substitution into ΔG = ΔH − TΔS so you can verify each step of the calculation.
Understanding the Results
The results show the Gibbs free energy change and its interpretation:
Spontaneous (ΔG < 0): The process can occur without external energy input. The reaction is thermodynamically favorable. Examples include combustion of fuels, dissolution of many salts in water, and the rusting of iron.
Non-spontaneous (ΔG > 0): The process requires energy input to proceed. Examples include electrolysis of water, photosynthesis (which requires light energy), and the decomposition of limestone. These processes can occur if coupled with an energy source.
At equilibrium (ΔG = 0): The forward and reverse processes occur at equal rates, and there is no net change. The system has reached its most stable state under the given conditions.
The temperature dependence is important: a process that is non-spontaneous at low temperature may become spontaneous at high temperature if the entropy term (TΔS) is large enough to overcome a positive enthalpy term. Conversely, an exothermic process may become non-spontaneous at very high temperatures if the entropy decreases.
The calculation chain at the bottom of the results shows the complete substitution, making it easy to verify the arithmetic and understand how each term contributes to the final ΔG value.
Real-World Applications
Gibbs free energy is the central concept in chemical engineering for predicting whether reactions will proceed and to what extent. The Haber process for ammonia synthesis (N₂ + 3H₂ → 2NH₃) is exothermic but has a negative ΔS. Understanding the temperature dependence of ΔG allows engineers to select the optimal temperature and pressure for maximum yield.
In materials science, ΔG determines phase stability. The phase diagrams of metals and alloys are essentially maps of Gibbs free energy vs. temperature and composition. Steel heat treatment, aluminum alloy aging, and semiconductor crystal growth all rely on predicting phase transformations using ΔG calculations.
Biochemistry uses Gibbs free energy to understand metabolic pathways. ATP hydrolysis (ΔG° ≈ −30.5 kJ/mol) drives many biological processes by coupling with endergonic reactions. The energy available from food oxidation, the efficiency of cellular respiration, and the energetics of protein folding are all ΔG questions.
Environmental chemistry applies ΔG to predict the stability of pollutants, the feasibility of remediation reactions, and the behavior of contaminants in soil and water. Understanding whether a contaminant will persist or degrade depends on the Gibbs free energy of the degradation pathway.
Worked Examples
Exothermic Reaction at Room Temperature
Problem:
Calculate ΔG for a reaction with ΔH = −120 kJ/mol and ΔS = −200 J/mol·K at 25°C.
Solution Steps:
- 1Convert temperature: T = 25 + 273.15 = 298.15 K
- 2Convert entropy: ΔS = −200 J/mol·K = −0.200 kJ/mol·K
- 3Apply equation: ΔG = ΔH − TΔS = −120 − (298.15 × −0.200)
- 4Calculate: ΔG = −120 + 59.63 = −60.37 kJ/mol
Result:
ΔG = −60.37 kJ/mol (spontaneous at 25°C).
Endothermic Reaction That Becomes Spontaneous
Problem:
A reaction has ΔH = +80 kJ/mol and ΔS = +150 J/mol·K. At what temperature does it become spontaneous?
Solution Steps:
- 1For spontaneity, ΔG < 0, so ΔH − TΔS < 0
- 2Rearrange: T > ΔH / ΔS = 80,000 / 150 = 533.3 K
- 3Convert to Celsius: 533.3 − 273.15 = 260.2°C
- 4At 25°C (298 K): ΔG = 80 − (298 × 0.150) = 80 − 44.7 = +35.3 kJ/mol (non-spontaneous)
Result:
The reaction becomes spontaneous above 260.2°C (533 K).
Temperature Effect on Spontaneity
Problem:
For ΔH = −50 kJ/mol and ΔS = +100 J/mol·K, is the reaction spontaneous at all temperatures?
Solution Steps:
- 1Since ΔH < 0 and ΔS > 0, both terms favor spontaneity
- 2At T = 0 K: ΔG = −50 − 0 = −50 kJ/mol (spontaneous)
- 3At T = 1000 K: ΔG = −50 − (1000 × 0.100) = −50 − 100 = −150 kJ/mol (spontaneous)
- 4ΔG is negative at all temperatures because both enthalpy and entropy favor the forward reaction
Result:
The reaction is spontaneous at all temperatures (ΔG < 0 for all T > 0).
Tips & Best Practices
- ✓Always convert temperature to Kelvin before calculating ΔG.
- ✓Convert ΔS from J/mol·K to kJ/mol·K (divide by 1000) before adding to ΔH.
- ✓A negative ΔG means spontaneous — the reaction can proceed without external energy.
- ✓Both ΔH < 0 and ΔS > 0 guarantee spontaneity at all temperatures.
- ✓For borderline cases, calculate the transition temperature T = ΔH / ΔS.
- ✓Use the standard free energy (ΔG°) with equilibrium constants, not the actual free energy.
Frequently Asked Questions
Sources & References
Last updated: 2026-06-06
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Editorial Note
MyCalcBuddy Editorial Team
This page is maintained as an educational calculator reference.
Formula Source: Chemistry: The Central Science
by Brown, LeMay, Bursten