Henderson-Hasselbalch Calculator
Calculate pH of buffer solutions using the Henderson-Hasselbalch equation
What Is the Henderson-Hasselbalch Equation?
The Henderson-Hasselbalch equation is one of the most important equations in acid-base chemistry. It relates the pH of a buffer solution to the pKa of the weak acid and the ratio of conjugate base to weak acid concentrations. The equation is pH = pKa + log([A⁻]/[HA]), where [A⁻] is the conjugate base concentration and [HA] is the weak acid concentration.
A buffer solution resists changes in pH when small amounts of acid or base are added. It consists of a weak acid (HA) and its conjugate base (A⁻) in comparable concentrations. The buffer works because the weak acid neutralizes added base, while the conjugate base neutralizes added acid. The Henderson-Hasselbalch equation allows you to calculate the pH of any buffer system.
When [A⁻] = [HA], the log term is zero and pH = pKa. This is the buffer capacity maximum — the buffer is most effective at resisting pH changes at pH = pKa. As the ratio [A⁻]/[HA] moves away from 1, the buffering capacity decreases. A useful buffer typically has pH within ±1 of pKa.
The equation is derived from the acid dissociation constant expression Ka = [H⁺][A⁻]/[HA], taking the negative logarithm of both sides. It assumes that the concentrations of HA and A⁻ are much larger than [H⁺] and [OH⁻], which is valid for dilute buffer solutions where the acid dissociation is small relative to the total buffer concentration.
This calculator computes the pH from pKa, base concentration, and acid concentration. It also displays the [A⁻]/[HA] ratio, which indicates how far the buffer is from its optimal pH = pKa point.
The Henderson-Hasselbalch Equation
The equation relates three measurable quantities and is the standard tool for buffer pH calculations.
Henderson-Hasselbalch Equation
Where:
- pH= pH of the buffer solution
- pKa= Negative log of the acid dissociation constant
- [A⁻]= Concentration of the conjugate base (mol/L)
- [HA]= Concentration of the weak acid (mol/L)
How to Use This Calculator
Follow these steps to calculate the pH of a buffer solution:
- Enter pKa: Input the negative logarithm of the acid dissociation constant for your weak acid. Common values: acetic acid (4.76), phosphoric acid (2.15, 7.20, 12.35), carbonic acid (6.35).
- Enter Base Concentration [A⁻]: Input the molar concentration of the conjugate base in mol/L. For an acetic acid/acetate buffer, this would be the acetate concentration.
- Enter Acid Concentration [HA]: Input the molar concentration of the weak acid in mol/L. For an acetic acid/acetate buffer, this would be the acetic acid concentration.
- View Results: The calculator displays the pH, the [A⁻]/[HA] ratio, and the complete calculation chain.
The [A⁻]/[HA] ratio tells you the buffer's position relative to its optimal pH = pKa point. A ratio of 1.0 means pH = pKa (optimal buffering). Ratios far from 1.0 indicate reduced buffering capacity.
Understanding the Results
The primary result is the pH of the buffer solution, displayed to three decimal places for precision.
[A⁻]/[HA] Ratio: This ratio determines how far the pH deviates from pKa. When the ratio equals 1, pH = pKa. When the ratio is 10, pH = pKa + 1. When the ratio is 0.1, pH = pKa − 1. This relationship is logarithmic — a tenfold change in ratio corresponds to one pH unit change.
Buffer Capacity: The buffer is most effective when the ratio is between 0.1 and 10 (pH = pKa ± 1). Outside this range, the buffer has limited capacity to resist pH changes because one component is present in much higher concentration than the other.
The calculation breakdown at the bottom shows the complete substitution: pH = pKa + log([A⁻]/[HA]). This makes it easy to verify the arithmetic and understand the contribution of each term. The logarithmic dependence means that small changes in the concentration ratio near 1.0 have relatively small effects on pH, while the same absolute changes at extreme ratios have larger effects.
The Henderson-Hasselbalch equation is most accurate for dilute solutions where [H⁺] and [OH⁻] are negligible compared to the buffer components. For very dilute buffers or extreme pH values, more rigorous methods are needed.
Real-World Applications
Buffer solutions are ubiquitous in chemistry, biology, and medicine. The blood buffer system (bicarbonate/CO₂, pKa = 6.35) maintains blood pH at 7.35-7.45, which is essential for enzyme function and oxygen transport. Deviations outside this range cause acidosis or alkalosis, which can be life-threatening.
Pharmaceutical formulations use buffers to maintain drug stability and bioavailability. Many drugs are weak acids or bases whose absorption depends on pH. The stomach's low pH (pH 1-3) favors absorption of weak acids, while the intestine's higher pH (pH 6-8) favors weak bases. Buffer systems in drug formulations control release rates.
Biological research relies on buffer systems to maintain pH in cell culture media, enzyme assays, and protein purification. Common biological buffers include Tris (pKa = 8.1), HEPES (pKa = 7.5), and phosphate (pKa = 7.2). Choosing the right buffer with a pKa near the desired pH is critical for experimental reproducibility.
Water treatment, food processing, and industrial chemistry all use buffer calculations to control pH. Soil pH affects nutrient availability for plants, and agricultural lime is added to raise soil pH based on buffer capacity calculations. The Henderson-Hasselbalch equation is the starting point for all these applications.
Worked Examples
Acetic Acid/Acetate Buffer
Problem:
Calculate the pH of a buffer containing 0.10 M acetic acid and 0.15 M sodium acetate (pKa = 4.76).
Solution Steps:
- 1Identify values: pKa = 4.76, [A⁻] = 0.15 M, [HA] = 0.10 M
- 2Calculate ratio: [A⁻]/[HA] = 0.15/0.10 = 1.5
- 3Apply equation: pH = 4.76 + log(1.5) = 4.76 + 0.176
- 4Result: pH = 4.936
Result:
The buffer pH is 4.94.
Equal Concentrations Buffer
Problem:
What is the pH when [A⁻] = [HA] = 0.050 M and pKa = 7.20?
Solution Steps:
- 1Identify values: pKa = 7.20, [A⁻] = 0.050 M, [HA] = 0.050 M
- 2Calculate ratio: [A⁻]/[HA] = 0.050/0.050 = 1.0
- 3Apply equation: pH = 7.20 + log(1.0) = 7.20 + 0
- 4Result: pH = 7.20 = pKa
Result:
The pH equals the pKa (7.20) because the concentrations are equal.
Aspirin Absorption
Problem:
Aspirin (acetylsalicylic acid) has pKa = 3.5. In the stomach at pH 2.0, what is the [A⁻]/[HA] ratio?
Solution Steps:
- 1Identify values: pKa = 3.5, pH = 2.0
- 2Rearrange equation: pH − pKa = log([A⁻]/[HA])
- 3Calculate: 2.0 − 3.5 = −1.5 = log([A⁻]/[HA])
- 4Convert: [A⁻]/[HA] = 10^(−1.5) = 0.0316
Result:
The ratio is 0.0316, meaning 97% of aspirin is in the protonated (HA) form, favoring absorption through the stomach lining.
Tips & Best Practices
- ✓Choose a buffer with pKa within ±1 of your target pH for maximum effectiveness.
- ✓Equal concentrations of acid and base give pH = pKa — this is the optimal buffering point.
- ✓A 10:1 ratio of base to acid gives pH = pKa + 1; a 1:10 ratio gives pH = pKa − 1.
- ✓Use the Henderson-Hasselbalch equation to design buffers for any target pH.
- ✓Blood pH is maintained at 7.35-7.45 by the bicarbonate buffer system (pKa = 6.35).
- ✓For very dilute buffers or extreme pH, use the exact equilibrium expression instead.
Frequently Asked Questions
Sources & References
Last updated: 2026-06-06
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Editorial Note
MyCalcBuddy Editorial Team
This page is maintained as an educational calculator reference.
Formula Source: Chemistry: The Central Science
by Brown, LeMay, Bursten