Vapor Pressure Calculator

Calculate vapor pressure of solutions using Raoult's Law

What Is Vapor Pressure?

Vapor pressure is the pressure exerted by a vapor in thermodynamic equilibrium with its condensed phase (solid or liquid) at a given temperature in a closed system. It represents the tendency of molecules to escape from the liquid or solid phase into the gas phase. A liquid with high vapor pressure evaporates readily, while one with low vapor pressure is less volatile.

Vapor pressure is a fundamental property that depends on temperature, the nature of the substance, and intermolecular forces. Stronger intermolecular forces (hydrogen bonding, dipole-dipole interactions) result in lower vapor pressure because more energy is required for molecules to escape the liquid phase. This is why water (with hydrogen bonding) has lower vapor pressure than ethanol (with weaker dipole-dipole interactions) at the same temperature.

When a non-volatile solute is dissolved in a solvent, the vapor pressure of the solvent decreases. This phenomenon, called vapor pressure lowering, is a colligative property that depends on the number of solute particles, not their identity. Raoult's Law quantitatively describes this effect: the vapor pressure of the solvent above a solution equals the mole fraction of the solvent multiplied by the vapor pressure of the pure solvent.

Vapor pressure measurements are essential for understanding boiling points, distillation processes, atmospheric chemistry, and the behavior of solutions. The boiling point of a liquid is the temperature at which its vapor pressure equals the external atmospheric pressure.

Raoult's Law

Raoult's Law states that the vapor pressure of a solvent above a solution is equal to the vapor pressure of the pure solvent multiplied by the mole fraction of the solvent in the solution. Mathematically: P = χ_solvent × P°_solvent, where P is the vapor pressure of the solvent above the solution, χ_solvent is the mole fraction of solvent, and P°_solvent is the vapor pressure of the pure solvent.

The vapor pressure lowering (ΔP) is the difference between the pure solvent vapor pressure and the solution vapor pressure: ΔP = P° − P = P°(1 − χ_solvent) = P° × χ_solute. This shows that vapor pressure lowering is directly proportional to the mole fraction of solute, making it a colligative property.

Raoult's Law applies ideally when the solute and solvent have similar molecular properties (similar size and intermolecular forces). Real solutions deviate from Raoult's Law, especially at high solute concentrations. Positive deviations occur when solute-solvent interactions are weaker than solvent-solvent interactions, while negative deviations occur when they are stronger.

For volatile solutes (where both solute and solvent contribute to the total vapor pressure), the total pressure is the sum of partial pressures from each component: P_total = χ_solvent × P°_solvent + χ_solute × P°_solute. This extended form is essential for understanding distillation of liquid mixtures.

Raoult's Law

P = χ_solvent × P°_solvent

Where:

  • P= Vapor pressure of solvent above the solution (mmHg or atm)
  • χ_solvent= Mole fraction of solvent in the solution (0 to 1)
  • P°_solvent= Vapor pressure of pure solvent at the same temperature (mmHg or atm)

How to Use This Calculator

This vapor pressure calculator applies Raoult's Law to determine the vapor pressure of a solvent above a solution. Follow these steps:

  1. Enter Pure Solvent Vapor Pressure: Input the vapor pressure of the pure solvent (P°) in mmHg at the temperature of interest. Common values: water at 25°C ≈ 23.8 mmHg, ethanol at 25°C ≈ 59.0 mmHg.
  2. Enter Mole Fraction of Solvent: Input the mole fraction of solvent (χ) in the solution, which must be between 0 and 1. A mole fraction of 1 represents pure solvent; lower values indicate more solute.
  3. Review Results: The calculator shows the solution vapor pressure, the vapor pressure lowering (ΔP), and the mole fraction of solute.

The formula used is P = χ × P°. The vapor pressure lowering ΔP = P° − P tells you how much the vapor pressure has been reduced by the presence of solute. The mole fraction of solute is 1 − χ, which is useful for verifying your input.

Understanding the Results

The solution vapor pressure (P) is the vapor pressure exerted by the solvent above the solution. It is always less than or equal to the pure solvent vapor pressure (P°). The reduction occurs because solute molecules occupy space at the liquid surface, reducing the number of solvent molecules that can escape into the vapor phase.

The vapor pressure lowering (ΔP) is the difference between pure solvent and solution vapor pressures: ΔP = P° − P. This value is directly proportional to the solute concentration (mole fraction). A larger ΔP indicates a more concentrated solution or a larger number of dissolved particles.

The mole fraction of solute (1 − χ) tells you the fraction of all particles in solution that are solute. For dilute solutions, the mole fraction of solute is approximately equal to the mole fraction of solute, which is useful for quick estimates.

Vapor pressure lowering is a colligative property, meaning it depends only on the number of dissolved particles, not their chemical identity. One mole of NaCl (which dissociates into 2 ions) produces twice the vapor pressure lowering of one mole of glucose (which does not dissociate).

Real-World Applications

Vapor pressure and Raoult's Law have numerous practical applications. In distillation, differences in vapor pressure between components allow separation of liquid mixtures. Fractional distillation exploits the fact that the vapor above a boiling liquid mixture is enriched in the more volatile component (higher vapor pressure), enabling separation of components with different boiling points.

In antifreeze and coolant design, the vapor pressure lowering effect of ethylene glycol in water raises the boiling point and lowers the freezing point of engine coolant. Understanding vapor pressure helps optimize coolant formulations for different temperature ranges.

Atmospheric chemistry uses vapor pressure data to predict the gas-particle partitioning of semi-volatile organic compounds. The vapor pressure determines whether a compound exists primarily in the gas phase or adsorbed onto atmospheric particles, affecting its transport, fate, and health effects.

In pharmaceutical development, vapor pressure measurements help characterize drug stability, predict sublimation behavior, and design drying processes. The vapor pressure of a drug substance affects its shelf life and storage requirements.

Food science uses vapor pressure data to optimize drying, packaging, and storage conditions. The water activity of food, related to water vapor pressure, determines microbial growth rates and chemical reaction rates that affect food quality and safety.

Worked Examples

Vapor Pressure of Salt Water

Problem:

Calculate the vapor pressure of water above a solution containing 0.10 mol fraction NaCl at 25°C. P°(water) = 23.8 mmHg.

Solution Steps:

  1. 1NaCl dissociates into 2 ions (Na⁺ and Cl⁻). The mole fraction of solute particles is 2 × 0.10 = 0.20.
  2. 2Mole fraction of solvent: χ_solvent = 1 − 0.20 = 0.80.
  3. 3Raoult's Law: P = χ_solvent × P° = 0.80 × 23.8 = 19.04 mmHg.
  4. 4Vapor pressure lowering: ΔP = 23.8 − 19.04 = 4.76 mmHg.

Result:

The vapor pressure above the salt water solution is 19.04 mmHg, a reduction of 4.76 mmHg from pure water.

Ethanol-Water Mixture

Problem:

For a solution with χ(ethanol) = 0.30 and P°(ethanol) = 59.0 mmHg at 25°C, what is the partial pressure of ethanol?

Solution Steps:

  1. 1Using Raoult's Law for ethanol: P_ethanol = χ_ethanol × P°_ethanol.
  2. 2P_ethanol = 0.30 × 59.0 = 17.7 mmHg.
  3. 3For water (χ_water = 0.70, P°_water = 23.8 mmHg): P_water = 0.70 × 23.8 = 16.66 mmHg.
  4. 4Total pressure = 17.7 + 16.66 = 34.36 mmHg.

Result:

The ethanol partial pressure is 17.7 mmHg. The total vapor pressure above the mixture is 34.36 mmHg.

Finding Mole Fraction from Vapor Pressure

Problem:

If the vapor pressure of water above a glucose solution is 22.0 mmHg at 25°C, what is the mole fraction of glucose?

Solution Steps:

  1. 1P°(water) = 23.8 mmHg, P = 22.0 mmHg.
  2. 2From Raoult's Law: χ_solvent = P / P° = 22.0 / 23.8 = 0.9244.
  3. 3Mole fraction of glucose = 1 − 0.9244 = 0.0756.
  4. 4Verification: P = 0.9244 × 23.8 = 22.0 mmHg ✓

Result:

The mole fraction of glucose is 0.0756. The solution contains about 7.6% glucose by mole fraction.

Tips & Best Practices

  • Remember that Raoult's Law applies to the solvent, not the solute, for non-volatile solutes.
  • For electrolytes, account for dissociation—one mole of NaCl produces 2 moles of particles.
  • Vapor pressure lowering is a colligative property: it depends on particle number, not identity.
  • Use the Clausius-Clapeyron equation to estimate vapor pressure at different temperatures.
  • Positive deviations from Raoult's Law occur when solute-solvent interactions are weaker than solvent-solvent.
  • Negative deviations occur when solute-solvent interactions are stronger (e.g., HCl in water).
  • At the boiling point, vapor pressure equals atmospheric pressure (1 atm = 760 mmHg at sea level).

Frequently Asked Questions

Raoult's Law applies ideally only to solutions where solute and solvent have similar molecular sizes and intermolecular forces. It works well for dilute solutions and for mixtures of chemically similar liquids (like benzene and toluene). It deviates significantly for concentrated solutions or when solute-solvent interactions differ greatly from solvent-solvent interactions. Modified versions of Raoult's Law account for non-ideal behavior using activity coefficients.
Vapor pressure is the pressure exerted by a vapor at equilibrium with its liquid at a given temperature. Boiling point is the temperature at which vapor pressure equals the external atmospheric pressure. A liquid with higher vapor pressure at a given temperature has a lower boiling point. Adding a non-volatile solute lowers vapor pressure and therefore raises the boiling point (boiling point elevation).
Solute molecules at the liquid surface reduce the number of solvent molecules available to escape into the vapor phase. Additionally, solute-solvent interactions can hold solvent molecules more tightly in the liquid phase. Both effects reduce the rate of evaporation, resulting in lower equilibrium vapor pressure. The effect depends only on the number of solute particles (colligative property), not their identity.
Vapor pressure increases exponentially with temperature, as described by the Clausius-Clapeyron equation. Higher temperature provides more kinetic energy for molecules to overcome intermolecular forces and escape into the vapor phase. The relationship is not linear—at higher temperatures, small temperature changes produce larger vapor pressure changes.
Vapor pressure is commonly expressed in mmHg (millimeters of mercury), atm (atmospheres), kPa (kilopascals), or Torr (equivalent to mmHg). The conversion: 1 atm = 760 mmHg = 101.325 kPa = 760 Torr. The choice of units depends on the application and regional conventions.

Sources & References

Last updated: 2026-06-06

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Editorial Note

MyCalcBuddy Editorial Team

This page is maintained as an educational calculator reference.

Source

Formula Source: Chemistry: The Central Science

by Brown, LeMay, Bursten

UpdatedLast reviewed: May 2026
CheckedFormula checks are based on standard references and internal QA review.