Cantilever Beam Calculator
Calculate moment, shear, deflection, and reinforcement requirements for cantilever concrete beams.
Cantilever Parameters
Maximum Moment at Support
89.60 k-ft
Service: 64.00 k-ft | Shear: 22.40 kips
Flexure
NG
Shear
Stirrups
Deflection
OK
Support Reactions
Vertical Reaction
16.00 kips
Moment Reaction
64.00 k-ft
Top Reinforcement (at support)
1.374 in²
rho = 0.739%
5-#5
4-#6
3-#7
phiMn Capacity
89.60 k-ft
phiVc Capacity
17.65 kips
Deflection at Free End
Delta = 1.010" (Limit: 533.333" = L/180)
Cantilever Beam Formulas
| Load Case | Max Moment | Max Shear | Max Deflection |
|---|---|---|---|
| Uniform Load (w) | wL²/2 | wL | wL⁴/8EI |
| Point Load at End (P) | PL | P | PL³/3EI |
| Point Load at (a) from support | Pa | P | Pa²(3L-a)/6EI |
What is a Cantilever Beam?
A cantilever beam is a structural element that is fixed or supported at one end and free at the other, projecting horizontally into space without any intermediate support. Unlike a simply supported beam that rests on supports at both ends, a cantilever beam derives its stability entirely from the fixed support, which must resist both the vertical reaction force and the bending moment caused by the applied loads. Cantilever beams are ubiquitous in engineering, appearing in balconies, diving boards, airplane wings, bridge spans, and building overhangs.
The structural behavior of a cantilever beam is fundamentally different from a simply supported beam. Under uniform loading, a simply supported beam has maximum moment at mid-span, while a cantilever beam has maximum moment at the fixed support. The free end of a cantilever deflects the most, while the fixed end has zero deflection and zero slope. This asymmetric behavior means that the reinforcement in a cantilever beam must be placed at the top of the beam at the support (where tension occurs), which is the opposite of a simply supported beam where reinforcement is at the bottom.
Cantilever beams are used when the span must extend beyond the last support, such as when a balcony projects from a building facade, when a roof overhang provides shade, or when a bridge must span an obstacle without intermediate piers. They are also used in construction as temporary structures, such as formwork brackets and scaffolding platforms, where the fixed end is attached to the completed structure and the free end provides a working platform.
This calculator analyzes cantilever beams under four loading conditions: uniform load, point load at the free end, point load at an intermediate position, and combined uniform plus point loading. It computes the maximum moment, shear, deflection, and reinforcement requirements using ACI 318 provisions for reinforced concrete design.
Cantilever Beam Formulas
Cantilever beams have distinct formulas for moment, shear, and deflection depending on the loading condition. The table below summarizes the key formulas for the three basic load cases.
| Load Case | Max Moment (at support) | Max Shear | Deflection (at free end) |
|---|---|---|---|
| Uniform Load (w) | wL²/2 | wL | wL⁴/8EI |
| Point Load at End (P) | PL | P | PL³/3EI |
| Point Load at (a) from support | Pa | P | Pa²(3L-a)/6EI |
Cantilever Moment (Uniform Load)
Where:
- w= Uniform distributed load (kips per foot)
- L= Cantilever length from fixed support (feet)
- Mmax= Maximum bending moment at the fixed support (ft-kips)
Reinforcement Design for Cantilevers
Reinforcing a cantilever beam requires careful attention to the tension zone location. In a cantilever under gravity loads, the top of the beam is in tension at the fixed support, which is the opposite of a simply supported beam. This means the primary longitudinal reinforcement must be placed at the top of the beam, extending from the fixed support along the tension zone.
The calculator computes the required steel area using the Whitney stress block method, which is the standard approach in ACI 318. The required reinforcement ratio is calculated from the factored moment, and the resulting steel area is compared against the minimum reinforcement requirement. The minimum steel ensures that the beam's moment capacity exceeds its cracking moment, preventing sudden failure upon first cracking.
The factored moment (Mu) includes a load factor of 1.4 applied to the service moment, which provides a safety margin for load uncertainty. The design moment capacity (φMn) includes a strength reduction factor of 0.9, which accounts for material variability, construction tolerances, and the consequences of failure.
Shear design is equally important for cantilever beams. The shear force is typically maximum at the fixed support and decreases toward the free end. The calculator checks whether the concrete alone can resist the shear force or whether stirrups (shear reinforcement) are required.
How to Use This Calculator
Follow these steps to analyze a cantilever beam:
- Enter Cantilever Length: Input the length of the cantilever from the fixed support to the free end in feet.
- Select Load Type: Choose from Uniform Load, Point Load at End, Point Load at Distance, or Combined Uniform + Point Load.
- Enter Load Values: Input the uniform load in kips/ft and/or the point load in kips, depending on the selected load type.
- Enter Beam Dimensions: Input the beam width and depth in inches. These are used to compute section properties and reinforcement requirements.
- Enter Material Properties: Input the concrete compressive strength (f'c) and steel yield strength (fy) in psi.
- Review Results: The calculator displays the maximum moment, shear, deflection, required reinforcement, capacity checks, and pass/fail indicators for flexure, shear, and deflection.
Real-World Applications
Cantilever beams are used extensively in building construction for balconies, canopies, overhangs, and sunshades. Residential balconies typically project 4-8 feet from the building face and are supported by cantilevered concrete or steel beams embedded in the floor structure. The design must account for the balcony's dead load, live load (typically 40 PSF for residential), and any additional loads from railings, furniture, or planters.
In bridge engineering, cantilever construction is used for medium-span bridges where intermediate piers are not feasible due to waterway navigation, deep valleys, or environmental constraints. The bridge is built outward from each pier in a cantilever fashion, with the segments joined at mid-span. This construction method eliminates the need for temporary falsework in the span below.
Commercial buildings often feature cantilevered canopies and entrance overhangs that provide weather protection without obstructing the ground-level space with columns. These elements must be designed for wind uplift, snow loads, and the weight of lighting and signage that may be attached to them.
In industrial applications, cantilever beams support crane runways, equipment platforms, and maintenance walkways. These structures may be subjected to dynamic loads from moving equipment, which require more conservative design approaches than static loading.
Worked Examples
Example 1: Uniform Load Cantilever
Problem:
An 8-foot cantilever beam (12" × 18") carries a uniform load of 2 kips/ft. Concrete f'c = 4,000 psi, steel fy = 60,000 psi. Find the maximum moment and required reinforcement.
Solution Steps:
- 1Maximum moment: Mmax = wL²/2 = 2 × 8²/2 = 64 ft-kips
- 2Factored moment: Mu = 1.4 × 64 = 89.6 ft-kips
- 3Effective depth: d = 18 - 2.5 = 15.5 inches
- 4Rn = (89.6 × 12,000) / (0.9 × 12 × 15.5²) = 443.2 psi
- 5Required rho = (0.85 × 4,000 / 60,000) × (1 - √(1 - 2 × 443.2 / (0.85 × 4,000))) = 0.0077
- 6Required As = 0.0077 × 12 × 15.5 = 1.43 in²
Result:
Maximum moment = 64 ft-kips. Required steel = 1.43 in² (use 3 - #7 bars = 1.80 in²).
Example 2: Point Load at Free End
Problem:
A 6-foot cantilever (12" × 16") carries a point load of 10 kips at the free end. Check shear capacity with f'c = 4,000 psi.
Solution Steps:
- 1Maximum shear: Vmax = P = 10 kips
- 2Factored shear: Vu = 1.4 × 10 = 14 kips
- 3Effective depth: d = 16 - 2.5 = 13.5 inches
- 4phiVc = 0.75 × 2 × √4000 × 12 × 13.5 / 1000 = 15.43 kips
- 5Check: Vu (14 kips) < phiVc (15.43 kips) — shear OK, no stirrups needed
Result:
Shear capacity (15.43 kips) exceeds demand (14 kips). No stirrups required.
Example 3: Deflection Check
Problem:
Check the deflection of a 10-foot cantilever (12" × 20") under 1.5 kips/ft uniform load. f'c = 4,000 psi.
Solution Steps:
- 1Ec = 57,000 × √4000 = 3,605,000 psi
- 2Ig = (12 × 20³) / 12 = 8,000 in⁴
- 3L = 10 ft = 120 inches
- 4w = 1.5 kips/ft = 125 lb/in
- 5Delta = wL⁴/(8EI) = 125 × 120⁴ / (8 × 3,605,000 × 8,000) = 0.934 inches
- 6Allowable = L/180 = 120/180 = 0.667 inches
- 7Check: 0.934 > 0.667 — deflection exceeds limit
Result:
Deflection = 0.934" exceeds L/180 limit (0.667"). Increase beam depth or reduce load.
Tips & Best Practices
- ✓Always place reinforcement at the TOP of a cantilever beam near the fixed support — this is where tension occurs.
- ✓Cantilever beams are more sensitive to deflection than simply supported beams — check deflection limits carefully.
- ✓For cantilever balconies, extend the floor slab reinforcement into the building for at least the cantilever length to resist negative moment.
- ✓Avoid adding loads near the free end of a cantilever — moment increases with distance from the support.
- ✓For long cantilevers, consider using a haunched (deeper) section at the fixed support where moment is highest.
- ✓Ensure the fixed support can resist both the vertical reaction and the moment — check the supporting wall or column.
- ✓For cantilevers longer than 8 feet, consult a structural engineer for detailed design and construction documents.
Frequently Asked Questions
Sources & References
Last updated: 2026-06-06
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Editorial Note
MyCalcBuddy Editorial Team
This page is maintained as an educational calculator reference.
Formula Source: Standard Mathematical References
by Various