Moment of Inertia Calculator

Calculate the moment of inertia (second moment of area) for common cross-sectional shapes used in structural engineering.

Section Shape

in
in

Moment of Inertia (Ix)

864.0000 in&sup4;

Ix (Strong Axis)
864.0000 in&sup4;
Iy (Weak Axis)
216.0000 in&sup4;
Sx (Section Modulus)
144.0000 in³
Sy (Section Modulus)
72.0000 in³
rx (Radius of Gyration)
3.4641 in
ry (Radius of Gyration)
1.7321 in
Area
72.0000 in²
Polar Moment (J)
1080.0000 in&sup4;

What is a Moment of Inertia Calculator?

A moment of inertia calculator determines the second moment of area (commonly called moment of inertia) for various cross-sectional shapes used in structural engineering. The moment of inertia is a geometric property that quantifies a cross-section's resistance to bending and deflection. A higher moment of inertia means the section is stiffer and deflects less under a given load. This property is essential for designing beams, columns, and other structural members where strength and serviceability (deflection limits) are both important design criteria.

The calculator supports four common cross-sectional shapes: rectangle, solid circle, hollow circle (pipe or tube), and I-beam. Each shape has distinct formulas for computing the moment of inertia about the strong axis (Ix) and weak axis (Iy). The strong axis is the axis about which the section has the greatest resistance to bending, typically the horizontal axis for beams loaded vertically. The weak axis is perpendicular to the strong axis and has less resistance to bending.

Beyond the moment of inertia, the calculator provides several other important section properties. The section modulus (S = I/c, where c is the distance from the neutral axis to the extreme fiber) is used to compute bending stress. The radius of gyration (r = √(I/A)) is used in column buckling calculations. The polar moment of inertia (J = Ix + Iy) is used for torsional analysis. The cross-sectional area is needed for axial load and weight calculations.

For I-beam sections, the calculator uses the parallel axis theorem to compute the moment of inertia. This theorem states that the moment of inertia about any axis equals the moment of inertia about the centroidal axis plus the product of the area and the square of the distance between the axes. The I-beam analysis sums the contributions of the two flanges and the web, each computed about the overall centroidal axis of the section.

Moment of Inertia Formulas

The moment of inertia formulas depend on the cross-sectional shape and the axis about which it is computed. For standard shapes, these formulas are derived from the integral definition: I = ∫ y² dA, where y is the distance from the neutral axis to the differential area element dA.

The section modulus and radius of gyration are derived from the moment of inertia and are used in different design contexts: section modulus for bending stress calculations and radius of gyration for column buckling analysis.

Section Property Formulas

Rectangle: Ix = bh³/12; Circle: Ix = πr⁴/4; Hollow Circle: Ix = π(R⁴-r⁴)/4; I-Beam: Ix = Σ(Ii + Ai·di²)

Where:

  • b= Width of the rectangular section in inches
  • h= Height of the rectangular section in inches
  • r= Radius of a solid circle in inches
  • R= Outer radius of a hollow circle in inches
  • I= Moment of inertia in inches to the fourth power
  • S= Section modulus (I/c) in inches cubed

How to Use This Calculator

Follow these steps to compute section properties for your structural shape:

  1. Select Shape Type: Choose from Rectangle, Solid Circle, Hollow Circle, or I-Beam.
  2. Enter Dimensions: For rectangles, enter width and height. For circles, enter the radius. For hollow circles, enter outer and inner radii. For I-beams, enter flange width, flange thickness, web height, and web thickness.
  3. Review Results: The calculator displays Ix (strong axis), Iy (weak axis), section moduli (Sx, Sy), radii of gyration (rx, ry), area, and polar moment of inertia (J).

Understanding the Results

The moment of inertia (Ix and Iy) is the primary output and is expressed in inches to the fourth power (in⁴). This value is used in beam deflection formulas, such as δ = 5wL⁴/(384EI) for a simply supported beam. A larger moment of inertia produces smaller deflections, making the member stiffer. The ratio Ix/Iy indicates how much stronger the section is about the strong axis compared to the weak axis.

The section modulus (Sx and Sy) is expressed in inches cubed (in³) and is used to compute bending stress: σ = M/S, where M is the applied bending moment. The section modulus directly relates to the strength of the section in bending. A section with a higher S value can resist a larger bending moment before exceeding the allowable stress.

The radius of gyration (rx and ry) is expressed in inches and is used in column slenderness ratio calculations: λ = KL/r. The slenderness ratio determines whether a column is classified as short, intermediate, or long, which affects the column's buckling capacity. A larger radius of gyration means the column is less prone to buckling.

Real-World Applications

Moment of inertia calculations are fundamental to structural engineering. Beam design and deflection control is the most common application. Building codes typically limit beam deflections to L/360 for live load and L/240 for total load. The required moment of inertia to meet these limits is determined from the deflection formula, and the engineer selects a beam section with adequate I value.

Column buckling analysis uses the radius of gyration (derived from the moment of inertia) to determine the slenderness ratio and buckling capacity. Long, slender columns with small radius of gyration are more susceptible to buckling and require larger sections or reduced unbraced lengths.

Composite beam analysis requires computing the moment of inertia of the transformed section, where the steel and concrete are converted to an equivalent single material using the modular ratio. The parallel axis theorem is applied to account for the different centroidal locations of the steel and concrete components.

Structural evaluation of existing buildings often involves measuring section dimensions and computing the actual moment of inertia to determine if existing members can support additional loads. This is common when buildings are renovated, repurposed, or when additional floors are added.

Worked Examples

Example 1: Rectangular Beam Section

Problem:

Calculate the section properties for a rectangular beam with width b = 12 inches and height h = 24 inches.

Solution Steps:

  1. 1Ix = bh³/12 = 12 × 24³/12 = 12 × 13,824/12 = 13,824 in⁴
  2. 2Iy = hb³/12 = 24 × 12³/12 = 24 × 1,728/12 = 3,456 in⁴
  3. 3Area = b × h = 12 × 24 = 288 in²
  4. 4Sx = Ix/(h/2) = 13,824/12 = 1,152 in³
  5. 5rx = √(Ix/A) = √(13,824/288) = √48 = 6.93 in

Result:

Ix = 13,824 in⁴, Iy = 3,456 in⁴, Area = 288 in², Sx = 1,152 in³, rx = 6.93 in.

Example 2: Hollow Circular Pipe

Problem:

Calculate the section properties for a steel pipe with outer radius R = 4 inches and inner radius r = 3.5 inches.

Solution Steps:

  1. 1Ix = Iy = π(R⁴ - r⁴)/4 = π(256 - 150.0625)/4 = π × 105.9375/4 = 83.23 in⁴
  2. 2Area = π(R² - r²) = π(16 - 12.25) = π × 3.75 = 11.78 in²
  3. 3Sx = Ix/R = 83.23/4 = 20.81 in³
  4. 4rx = √(Ix/A) = √(83.23/11.78) = √7.065 = 2.66 in
  5. 5J = Ix + Iy = 2 × 83.23 = 166.46 in⁴

Result:

Ix = Iy = 83.23 in⁴, Area = 11.78 in², Sx = 20.81 in³, J = 166.46 in⁴.

Example 3: I-Beam Section

Problem:

Calculate the moment of inertia for an I-beam with flange width 8 inches, flange thickness 0.5 inches, web height 10 inches, and web thickness 0.375 inches.

Solution Steps:

  1. 1Total height = 10 + 2 × 0.5 = 11 inches
  2. 2Flange Ix (each) = (8 × 0.5³)/12 + 8 × 0.5 × (10/2 + 0.5/2)² = 0.0833 + 4 × 27.5625 = 110.33 in⁴
  3. 3Web Ix = (0.375 × 10³)/12 = 31.25 in⁴
  4. 4Total Ix = 2 × 110.33 + 31.25 = 251.91 in⁴
  5. 5Area = 2 × 8 × 0.5 + 10 × 0.375 = 8 + 3.75 = 11.75 in²
  6. 6Sx = Ix/(11/2) = 251.91/5.5 = 45.80 in³

Result:

Ix = 251.91 in⁴, Area = 11.75 in², Sx = 45.80 in³.

Tips & Best Practices

  • Always check both Ix and Iy because the weak-axis moment of inertia often governs for columns and unbraced beams.
  • For built-up sections, use the parallel axis theorem to sum the contributions of each component about the overall centroid.
  • The moment of inertia is always expressed in length to the fourth power (in⁴ or mm⁴), not in area units.
  • When comparing sections, the section modulus is often more useful than the moment of inertia for quick strength comparisons.
  • For composite sections (steel-concrete), transform the section to an equivalent single material before computing I.
  • Hollow circular sections are very efficient for shafts and columns because they maximize the polar moment of inertia for a given weight.
  • The radius of gyration is always less than the radius of gyration of a solid section with the same outer dimensions, reflecting the reduced material distribution.

Frequently Asked Questions

The moment of inertia (I) is the second moment of area about a single axis (usually the bending axis) and resists bending. The polar moment of inertia (J = Ix + Iy) is the second moment of area about the axis perpendicular to the cross-section (the longitudinal axis of the member) and resists torsion (twisting). Both are computed from the same fundamental concept but about different axes.
The I-beam shape places most of the material in the flanges, which are located far from the neutral axis. Since the moment of inertia depends on the square of the distance from the neutral axis (I = ∫ y² dA), placing material at the extreme distances maximizes the moment of inertia for a given amount of material. The thin web connects the flanges and resists shear forces. This makes the I-beam much more efficient than a solid rectangular section of equal weight.
Beam deflection is inversely proportional to the moment of inertia. For a simply supported beam with uniform load, the deflection is δ = 5wL⁴/(384EI), meaning doubling the moment of inertia halves the deflection. This is why deflection-sensitive applications often require deeper beams or sections with higher moments of inertia, even if the strength requirement is already met.
The section modulus (S = I/c) is used to compute bending stress: σ = M/S, where M is the applied bending moment and c is the distance from the neutral axis to the extreme fiber. The maximum bending stress must not exceed the allowable stress for the material. The section modulus is a convenient way to compare the bending strength of different sections without computing the full stress distribution.
Yes, the moment of inertia (or more precisely, the radius of gyration r = √(I/A)) is used in column buckling calculations. The slenderness ratio λ = KL/r determines the column's susceptibility to buckling. Columns with small radius of gyration are more slender and more likely to buckle under axial load. The moment of inertia about the weak axis typically governs because the column will buckle about the axis with the least resistance.

Sources & References

Last updated: 2026-06-06

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Editorial Note

MyCalcBuddy Editorial Team

This page is maintained as an educational calculator reference.

Source

Formula Source: Standard Mathematical References

by Various

UpdatedLast reviewed: May 2026
CheckedFormula checks are based on standard references and internal QA review.

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