Nuclear Binding Energy Calculator
Calculate nuclear binding energy from mass defect using E=mc²
Common Nuclei
Formulas Used
Mass defect: Δm = Z·m_p + N·m_n - M_nucleus
Binding energy: E_B = Δm × c² = Δm × 931.5 MeV/u
1 u = 931.5 MeV/c²
What Is Nuclear Binding Energy?
Nuclear binding energy is the energy required to disassemble a nucleus into its constituent protons and neutrons. It represents the net energy released when nucleons bind together through the strong nuclear force. Per Einstein's E = mc², the total mass of a bound nucleus is less than the sum of its individual nucleons' masses — this mass difference is called the mass defect, and multiplying it by c² yields the binding energy.
Astonishingly, the binding energy of a single uranium-235 nucleus is about 1,783 MeV — roughly 7.6 MeV per nucleon. Fissioning one U-235 nucleus into lighter fragments releases about 200 MeV of usable energy (the difference in binding energy per nucleon between uranium and the fission products). This is why a few kilograms of uranium can power a city: the nuclear binding energy scale is roughly a million times larger than chemical bond energies (eV vs MeV).
Mass Defect and Binding Energy Formulas
The calculation uses experimentally measured atomic masses and the semi-empirical mass formula (Bethe-Weizsäcker formula) as a theoretical cross-check:
Binding Energy Equations
Where:
- Δm= Mass defect in atomic mass units (u)
- Z, N= Number of protons and neutrons
- mₚ, mₙ= Proton mass (1.007276 u) and neutron mass (1.008665 u)
- E_B= Total binding energy (MeV)
- aᵥ, aₛ, aᶜ, aₐ= Volume (15.8), Surface (18.3), Coulomb (0.714), Asymmetry (23.2) coefficients
- δ= Pairing term: +12/√A for even-even, −12/√A for odd-odd, 0 for odd-A
Binding Energy per Nucleon — The Stability Curve
Binding energy per nucleon (BE/A) reveals nuclear stability trends across the periodic table:
| Nucleus | A | BE/A (MeV) | Significance |
|---|---|---|---|
| ²H | 2 | 1.11 | Weakly bound — explains why deuterium is rare |
| ⁴He | 4 | 7.07 | Exceptionally stable — alpha particle |
| ¹²C | 12 | 7.68 | Triple-alpha process product |
| ⁵⁶Fe | 56 | 8.79 | The most tightly bound nucleus — peak of the curve |
| ²³⁵U | 235 | 7.59 | Fissionable — splits into higher BE/A products |
Iron-56 sits at the peak of the curve — no nuclear reaction (fusion or fission) involving iron can release net energy. This is why stars stop fusing elements at iron, leading to core-collapse supernovae. The curve's shape explains why energy is released both by fusing light nuclei (stars, hydrogen bombs) and by fissioning heavy ones (reactors, atomic bombs).
How to Use This Calculator
- Enter Protons (Z): The atomic number determines which element you're analyzing.
- Enter Neutrons (N): Together with Z, this gives the mass number A = Z + N.
- Enter Atomic Mass: Provide the experimentally measured atomic mass in atomic mass units (u), to at least 6 decimal places for accuracy. Use the common nuclei quick-select buttons for well-known isotopes.
- Review Results: Mass defect in both u and kg, total binding energy in MeV and joules, binding energy per nucleon (the key indicator of stability), and the semi-empirical mass formula estimate for comparison. The stability rating indicates whether the nucleus is highly stable (>7.5 MeV/nucleon), moderately stable, or weakly bound.
Real-World Applications
Binding energy is the physics behind nuclear power. Fission reactors exploit the fact that uranium-235 (BE/A ≈ 7.59 MeV) splits into medium-mass fragments like krypton and barium (BE/A ≈ 8.5 MeV), releasing about 0.9 MeV per nucleon as useful energy. A single U-235 fission yields ~200 MeV — compared to ~4 eV for burning a carbon atom, this is a 50-million-fold energy density advantage that makes nuclear power so compact.
In astrophysics, binding energy governs stellar evolution. Stars fuse hydrogen to helium (BE/A from 0 to 7.07 MeV), then helium to carbon and oxygen, progressively climbing the binding energy curve. Each fusion stage releases less energy per nucleon than the last. When the core reaches iron (peak of the curve), fusion becomes endothermic — the star can no longer support itself against gravity. The resulting gravitational collapse triggers a supernova, synthesizing all elements heavier than iron through rapid neutron capture (r-process).
Worked Examples
Iron-56 — The Most Stable Nucleus
Problem:
⁵⁶Fe has Z=26, N=30, and atomic mass 55.934937 u. Calculate its mass defect and binding energy per nucleon.
Solution Steps:
- 1Expected mass: 26 × 1.007276 + 30 × 1.008665 = 26.18918 + 30.25995 = 56.44913 u
- 2Nuclear mass ≈ 55.934937 − 26 × 0.000549 = 55.92066 u
- 3Mass defect: Δm = 56.44913 − 55.92066 = 0.52847 u
- 4Binding energy: E_B = 0.52847 × 931.5 = 492.3 MeV
- 5BE per nucleon: 492.3/56 = 8.79 MeV/nucleon
Result:
Binding energy per nucleon = 8.79 MeV/nucleon — the highest of any known nucleus. ⁵⁶Fe is the ultimate endpoint of stellar fusion in massive stars.
Deuterium — The Weakest Bound Stable Nucleus
Problem:
²H (deuterium) has Z=1, N=1, atomic mass 2.014102 u. Calculate its binding energy.
Solution Steps:
- 1Expected mass: 1 × 1.007276 + 1 × 1.008665 = 2.015941 u
- 2Nuclear mass ≈ 2.014102 − 1 × 0.000549 = 2.013553 u
- 3Mass defect: Δm = 2.015941 − 2.013553 = 0.002388 u
- 4Binding energy: E_B = 0.002388 × 931.5 = 2.224 MeV
- 5BE per nucleon: 2.224/2 = 1.112 MeV/nucleon
Result:
Binding energy per nucleon = 1.11 MeV/nucleon — the lowest of any stable nucleus. This explains deuterium's cosmic rarity and why it fuses so readily at relatively low temperatures in stars.
Uranium-235 Fission Energy
Problem:
²³⁵U has Z=92, N=143, atomic mass 235.043930 u. Calculate BE/A and estimate fission energy release.
Solution Steps:
- 1Expected mass: 92 × 1.007276 + 143 × 1.008665 = 92.6694 + 144.2391 = 236.9085 u
- 2Nuclear mass ≈ 235.043930 − 92 × 0.000549 = 234.99339 u
- 3Mass defect: Δm = 236.9085 − 234.99339 = 1.9151 u
- 4Binding energy: 1.9151 × 931.5 = 1783.9 MeV; BE/A = 1783.9/235 = 7.59 MeV/nucleon
- 5Fission products at BE/A ≈ 8.5 MeV/nucleon: energy release ≈ (8.5 − 7.59) × 235 ≈ 214 MeV
Result:
BE/A = 7.59 MeV/nucleon. Fission to medium-mass products releases approximately 210-215 MeV per nucleus — consistent with the well-known ~200 MeV per ²³⁵U fission.
Tips & Best Practices
- ✓Precision matters — use atomic masses with at least 6 decimal places for meaningful mass defect calculations
- ✓Remember to subtract electron masses from the atomic mass to get nuclear mass (Z × 0.000549 u)
- ✓The semi-empirical formula estimate is a cross-check, not a replacement for measured values — shell effects cause deviations at magic numbers
- ✓Steeper binding energy per nucleon means less stable — nuclei below 7 MeV/nucleon are candidates for fission or fusion
- ✓1 u = 931.494 MeV/c² — this conversion factor is essential for all nuclear physics calculations
Frequently Asked Questions
Sources & References
Last updated: 2026-06-06
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Editorial Note
MyCalcBuddy Editorial Team
This page is maintained as an educational calculator reference.
Formula Source: University Physics
by Young & Freedman