Nernst Equation Calculator
Calculate electrode potential at non-standard concentrations
Oxidized Form (Ox)
Reduced Form (Red)
About the Nernst Equation
The Nernst equation relates electrode potential to the standard potential and the concentrations of chemical species involved. It shows how potential changes from standard conditions.
At 25°C: E = E° - (0.0592/n)log₁₀(Q)
A 10-fold change in concentration ratio changes the potential by ~59.2/n mV.
What Is the Nernst Equation?
The Nernst equation calculates the electrode potential of an electrochemical cell under non-standard conditions. It relates the actual cell potential to the standard electrode potential, temperature, number of electrons transferred, and the concentrations of reactants and products. Named after Walther Nernst (Nobel Prize in Chemistry, 1920), this equation is fundamental to electrochemistry and explains how concentration changes affect cell voltage.
Under standard conditions (1 M concentrations, 1 atm pressure, 25°C), every electrochemical half-reaction has a characteristic standard electrode potential (E°). The Nernst equation adjusts this standard potential for the actual concentrations present in the cell. When the reaction quotient Q equals 1 (all concentrations at standard values), the correction term vanishes and E equals E°. As concentrations deviate from standard, the cell potential shifts accordingly.
This calculator allows you to enter the standard electrode potential, temperature, number of electrons transferred, and the concentrations and stoichiometric coefficients of both the oxidized and reduced forms. It computes the electrode potential, the potential shift from standard conditions, and whether the cell is more oxidizing or reducing than at standard conditions.
The Nernst Equation
The Nernst equation relates electrode potential to the standard potential and the reaction quotient, accounting for the non-standard concentrations of all species involved.
Nernst Equation
Where:
- E= Electrode potential at non-standard conditions (V)
- E°= Standard electrode potential (V)
- R= Universal gas constant (8.314 J/(mol·K))
- T= Absolute temperature (K)
- n= Number of electrons transferred in the half-reaction
- F= Faraday constant (96,485 C/mol)
- Q= Reaction quotient = [Red]^aRed / [Ox]^aOx
How to Use This Calculator
This calculator supports detailed Nernst equation calculations with stoichiometric coefficients:
- Enter Standard Electrode Potential (E°): Input the standard potential in volts for the half-reaction.
- Enter Temperature: Default is 298.15 K (25°C). Adjust for non-standard temperatures.
- Enter Electrons Transferred (n): The number of electrons in the balanced half-reaction.
- Enter Oxidized Form Details: Concentration in molarity and stoichiometric coefficient.
- Enter Reduced Form Details: Concentration in molarity and stoichiometric coefficient.
- View Results: The electrode potential, potential shift, reaction quotient, and condition (more oxidizing/reducing) are displayed.
Interpreting the Results
The electrode potential (E) is the actual voltage of the half-reaction at the given concentrations. A positive shift from E° means the cell is more oxidizing than at standard conditions; a negative shift means it is more reducing.
The reaction quotient Q quantifies how far the system is from equilibrium. When Q < 1 (more products relative to reactants at equilibrium), the ln(Q) term is negative, making E more positive than E°. When Q > 1, the correction is positive, making E less positive (or more negative) than E°.
The Nernst coefficient (RT/nF) determines the sensitivity of the potential to concentration changes. At 25°C with n = 1, this coefficient is 25.69 mV. A tenfold change in Q shifts the potential by 59.2/n mV at 25°C, which is a useful rule of thumb for quick estimates.
The condition indicator tells you whether the half-cell is more oxidizing (higher tendency to accept electrons) or more reducing (higher tendency to donate electrons) compared to standard conditions.
Real-World Applications
The Nernst equation is essential in battery design and analysis. The voltage of a battery changes as it discharges because reactant concentrations decrease and product concentrations increase. The Nernst equation predicts this voltage decline and helps engineers design batteries that maintain stable output over their useful life.
In biological systems, the Nernst equation calculates equilibrium potentials for ion channels across cell membranes. The resting membrane potential of neurons is determined by the Nernst potentials for K⁺, Na⁺, and Cl⁻ weighted by their membrane permeabilities.
In analytical chemistry, ion-selective electrodes use the Nernst equation to convert measured voltages into ion concentrations. pH meters, fluoride electrodes, and calcium sensors all rely on this relationship for quantitative measurements.
In corrosion science, the Nernst equation predicts which metals will corrode under specific environmental conditions and guides the design of cathodic protection systems for pipelines, ships, and bridges.
Worked Examples
Copper Half-Cell
Problem:
Calculate the electrode potential for Cu²⁺/Cu (E° = 0.34 V) with [Cu²⁺] = 0.01 M at 25°C and n = 2.
Solution Steps:
- 1Q = [Cu²⁺] = 0.01 (reduced form is solid Cu, activity = 1)
- 2E = E° − (RT/nF) × ln(Q) = 0.34 − (0.02569/2) × ln(0.01)
- 3E = 0.34 − 0.01285 × (−4.605) = 0.34 + 0.0592 = 0.399 V
- 4The potential shift is +59.2 mV, more oxidizing than standard
Result:
E = 0.399 V (+59.2 mV shift from standard, more oxidizing)
Concentration Cell
Problem:
A concentration cell has [Zn²⁺]₁ = 1.0 M and [Zn²⁺]₂ = 0.001 M. E° = 0 V for a concentration cell. Calculate the cell potential at 25°C.
Solution Steps:
- 1Q = [Zn²⁺]₂ / [Zn²⁺]₁ = 0.001 / 1.0 = 0.001
- 2n = 2 for Zn²⁺/Zn
- 3E = 0 − (0.02569/2) × ln(0.001) = −0.01285 × (−6.908)
- 4E = 0.0888 V
Result:
E = 0.0888 V (concentration difference drives the cell voltage)
Temperature Effect
Problem:
For a half-reaction with E° = 0.77 V and n = 1, what is E at 50°C (323.15 K) when Q = 10?
Solution Steps:
- 1RT/nF at 323.15 K = (8.314 × 323.15) / (1 × 96485) = 0.02786 V
- 2E = 0.77 − 0.02786 × ln(10) = 0.77 − 0.02786 × 2.303
- 3E = 0.77 − 0.0641 = 0.706 V
Result:
E = 0.706 V (higher temperature increases sensitivity to concentration)
Tips & Best Practices
- ✓At 25°C, use the simplified form: E = E° − (0.0592/n) × log₁₀(Q) for quick calculations.
- ✓A tenfold change in concentration ratio shifts potential by 59.2/n mV at 25°C.
- ✓Remember: Q = [products] / [reactants], each raised to stoichiometric coefficients.
- ✓For solid and pure liquid species, the activity is 1 — they don't appear in Q.
- ✓Higher temperatures increase the sensitivity of potential to concentration changes.
- ✓The potential shift indicates whether the cell is more oxidizing (positive shift) or reducing (negative shift) than standard.
Frequently Asked Questions
Sources & References
Last updated: 2026-06-06
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Editorial Note
MyCalcBuddy Editorial Team
This page is maintained as an educational calculator reference.
Formula Source: Chemistry: The Central Science
by Brown, LeMay, Bursten