Phase Diagram Calculator

Determine the phase of a substance at given temperature and pressure. Find triple and critical points.

Conditions

24.9 C / 76.7 F

1.0000 atm / 101.33 kPa

Quick Conditions:

Phase at Given Conditions

Liquid

Pressure above vapor pressure curve

TReduced Temp (Tr)
0.461
PReduced Press (Pr)
0.004592
PvVapor Pressure
2.72 kPa
TbNormal BP
373.1 K

Triple Point:

T = 273.16 K (0.01 C)

P = 0.6117 kPa

Critical Point:

Tc = 647.10 K (373.95 C)

Pc = 22.06 MPa

Phase Diagram Features

Triple Point

Unique T and P where all three phases coexist in equilibrium.

Critical Point

Above this, no distinction between liquid and gas phases.

Supercritical

Properties of both liquid and gas above critical point.

What Is a Phase Diagram?

A phase diagram is a graphical representation of the conditions of temperature and pressure under which a substance exists as a solid, liquid, gas, or supercritical fluid. Phase diagrams are among the most important tools in thermodynamics and physical chemistry because they summarize all the phase behavior of a substance in a single chart. The boundaries between regions on the phase diagram represent phase transitions — conditions where two phases coexist in equilibrium. Understanding phase diagrams is essential for predicting how a substance will behave under different conditions, from everyday situations (will ice melt at room temperature?) to extreme environments (what happens to water at the center of the Earth?).

Every pure substance has a unique phase diagram with several key features. The triple point is the specific temperature and pressure where all three common phases (solid, liquid, gas) coexist simultaneously in equilibrium. For water, the triple point is at 273.16 K (0.01°C) and 611.73 Pa (0.006 atm). The critical point marks the temperature and pressure above which the distinction between liquid and gas disappears, creating a supercritical fluid. Water's critical point is at 647.1 K (373.9°C) and 22.064 MPa (218 atm). The normal boiling point and normal melting point are the phase transition temperatures at standard atmospheric pressure (1 atm = 101.325 kPa).

This calculator determines the phase of a substance at specified temperature and pressure conditions by applying the Clausius-Clapeyron equation to estimate vapor pressures and comparing them to the input conditions. It supports six common substances: water, carbon dioxide, ammonia, ethanol, oxygen, and nitrogen.

The Clausius-Clapeyron Equation

The phase boundaries on a phase diagram are described by the Clausius-Clapeyron equation, which relates vapor pressure to temperature along the liquid-gas boundary.

Clausius-Clapeyron Equation

ln(P₂/P₁) = (ΔHvap / R) × (1/T₁ - 1/T₂)

Where:

  • P₁= Vapor pressure at reference temperature T₁ (Pa)
  • P₂= Vapor pressure at temperature T₂ (Pa)
  • ΔHvap= Enthalpy of vaporization (J/mol)
  • R= Ideal gas constant = 8.314 J/(mol·K)
  • T₁, T₂= Absolute temperatures (K)

How to Use This Calculator

This calculator determines the phase of a substance at specified conditions:

  1. Select a Substance: Choose from water (H₂O), carbon dioxide (CO₂), ammonia (NH₃), ethanol (C₂H₅OH), oxygen (O₂), or nitrogen (N₂).
  2. Set Temperature: Enter the temperature in Kelvin. The calculator also shows the equivalent values in °C and °F for convenience.
  3. Set Pressure: Enter the pressure in Pascals (Pa). The calculator shows equivalents in atm and kPa.
  4. Use Quick Conditions: Click preset buttons for STP (298 K, 101325 Pa), 0°C at 1 atm, or 100°C at 1 atm for common reference states.
  5. View Results: The calculator identifies the phase, provides details about the phase determination, and shows key thermodynamic properties including the triple point, critical point, reduced temperature and pressure, and estimated vapor pressure.

The reduced temperature (Tr = T/Tc) and reduced pressure (Pr = P/Pc) are dimensionless values that allow comparison across different substances using the principle of corresponding states.

Understanding the Results

The calculator provides comprehensive information about the substance's phase behavior:

Phase Identification: The primary result identifies the phase at the specified conditions: Solid, Liquid, Gas/Vapor, Supercritical Fluid, or a coexistence region. The phase details explain why that phase is present (e.g., "Above vapor pressure curve — liquid phase stable").

Triple Point: The temperature and pressure where all three phases coexist. Below the triple point pressure, the substance cannot exist as a liquid — it sublimes directly from solid to gas. This is why dry ice (solid CO₂) sublimes at room pressure rather than melting.

Critical Point: The temperature and pressure above which the liquid-gas distinction disappears. Above the critical point, the substance is a supercritical fluid with properties of both liquids (density) and gases (diffusivity). Supercritical CO₂ is widely used as a green solvent for decaffeination and extraction processes.

Reduced Properties: The reduced temperature and pressure (Tr and Pr) are dimensionless ratios that normalize the conditions relative to the critical point. According to the principle of corresponding states, all substances at the same Tr and Pr have similar thermodynamic properties, allowing predictions for one substance based on data from another.

Vapor Pressure: The estimated vapor pressure at the specified temperature, calculated using the Clausius-Clapeyron equation. This value helps determine whether the substance is above or below the liquid-gas equilibrium boundary.

Real-World Applications

Phase diagrams and phase behavior calculations have critical applications across science and engineering:

Supercritical Fluid Technology: Supercritical CO₂ (Tc = 31.1°C, Pc = 73.8 bar) is used as a green solvent for decaffeinating coffee, extracting essential oils, dry cleaning, and pharmaceutical processing. Operating above the critical point eliminates the need for organic solvents, making the process more environmentally friendly and producing cleaner products.

Cryogenics and Refrigeration: The phase behavior of nitrogen (boiling point 77.36 K = -195.79°C) and helium makes them essential cryogens. Liquid nitrogen is used for preserving biological samples,冷却 superconducting magnets, and flash-freezing food. Understanding phase diagrams is essential for designing and operating cryogenic storage and transport systems.

Geology and Planetary Science: The phase diagram of water explains phenomena like glacier flow (pressure melting), volcanic eruptions (degassing of magma), and the possible existence of liquid water on other planets. The phase diagrams of minerals at extreme pressures explain the structure of the Earth's mantle and core.

Industrial Process Design: Chemical engineers use phase diagrams to design distillation columns, crystallization processes, and gas separation systems. The vapor-liquid equilibrium data extracted from phase diagrams determines the number of theoretical stages needed for separation and the energy requirements of the process.

Worked Examples

Water at Room Temperature

Problem:

Determine the phase of water at 298 K (25°C) and 101,325 Pa (1 atm).

Solution Steps:

  1. 1Water properties: Tt = 273.16 K, Tc = 647.1 K, Pt = 611.73 Pa, Pc = 22,064,000 Pa
  2. 2T = 298 K is between Tt and Tc
  3. 3P = 101,325 Pa is between Pt and Pc
  4. 4Calculate vapor pressure using Clausius-Clapeyron: Pvap ≈ 3,169 Pa at 298 K
  5. 5Since P (101,325 Pa) > Pvap (3,169 Pa), the stable phase is liquid

Result:

Phase: Liquid — water is a liquid at room temperature and standard pressure, as expected

Carbon Dioxide at 1 atm

Problem:

Determine the phase of CO₂ at 250 K and 101,325 Pa (1 atm).

Solution Steps:

  1. 1CO₂ properties: Tt = 216.55 K, Pt = 517,000 Pa, Tc = 304.25 K, Pc = 7,386,000 Pa
  2. 2T = 250 K is between Tt and Tc
  3. 3P = 101,325 Pa is below the triple point pressure (517,000 Pa)
  4. 4Below the triple point pressure, CO₂ cannot exist as a liquid
  5. 5CO₂ sublimes directly from solid to gas at 1 atm

Result:

Phase: Gas/Vapor — CO₂ at 1 atm and 250 K is a gas because the pressure is below the triple point

Supercritical Water

Problem:

Determine the phase of water at 700 K and 30,000,000 Pa (300 atm).

Solution Steps:

  1. 1Water properties: Tc = 647.1 K, Pc = 22,064,000 Pa
  2. 2T = 700 K > Tc (647.1 K)
  3. 3P = 30,000,000 Pa > Pc (22,064,000 Pa)
  4. 4Both temperature and pressure exceed the critical point

Result:

Phase: Supercritical Fluid — water above its critical point has no distinct liquid or gas phase; it is used in supercritical water oxidation processes

Tips & Best Practices

  • The triple point is the lowest pressure at which a liquid phase can exist for a given substance.
  • Supercritical fluids combine liquid-like density with gas-like diffusivity — excellent for extraction.
  • Below the triple point pressure, substances sublime (solid → gas) rather than melt.
  • Water is unusual: its solid phase (ice) is less dense than its liquid phase, causing the melting curve to slope left.
  • Use reduced properties (Tr, Pr) to compare phase behavior across different substances.
  • Dry ice sublimes at room pressure because 1 atm is below CO₂'s triple point pressure of 5.17 atm.

Frequently Asked Questions

The triple point is the unique temperature and pressure at which all three common phases (solid, liquid, and gas) of a substance coexist simultaneously in thermodynamic equilibrium. For water, the triple point is at 273.16 K (0.01°C) and 611.73 Pa (0.006 atm). Below the triple point pressure, a substance cannot exist as a liquid — it sublimes directly from solid to gas.
Above the critical temperature and pressure, the distinction between liquid and gas phases disappears, creating a supercritical fluid. A superercritical fluid has the density of a liquid but the diffusivity and viscosity of a gas, making it an excellent solvent. Supercritical CO₂ is widely used for decaffeination, extraction, and dry cleaning because it is non-toxic, non-flammable, and easily removed by depressurization.
Dry ice (solid CO₂) sublimes at room pressure because atmospheric pressure (101,325 Pa) is below CO₂'s triple point pressure (517,000 Pa). Below the triple point, liquid CO₂ cannot exist, so the solid converts directly to gas. To observe liquid CO₂, you must apply at least 517,000 Pa of pressure. This is why CO₂ fire extinguishers store the compound as a liquid under high pressure.
The Clausius-Clapeyron equation describes the liquid-gas boundary (vaporization curve) on a phase diagram. It quantifies how vapor pressure increases with temperature along this boundary. The equation assumes that the gas phase behaves ideally and that the enthalpy of vaporization is constant over the temperature range. It is used to estimate vapor pressures at temperatures where direct measurements are unavailable.
Yes. Water can exist as a liquid below 0°C at pressures above the melting curve on the phase diagram. For example, at the bottom of deep ocean trenches, the high pressure lowers the melting point of water slightly, allowing liquid water to exist at temperatures just below 0°C. Additionally, supercooled water (liquid water below 0°C) can exist temporarily in the absence of nucleation sites.

Sources & References

Last updated: 2026-06-06

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Editorial Note

MyCalcBuddy Editorial Team

This page is maintained as an educational calculator reference.

Source

Formula Source: Chemistry: The Central Science

by Brown, LeMay, Bursten

UpdatedLast reviewed: May 2026
CheckedFormula checks are based on standard references and internal QA review.