Clausius-Clapeyron Calculator

Calculate vapor pressure, temperature, or enthalpy of vaporization using the Clausius-Clapeyron equation.

Clausius-Clapeyron Equation

Solve For:

1 atm
0 atm10 atm
atm
373 K
200 K600 K
K

= 100.00 °C

358 K
200 K600 K
K

= 85.00 °C

41 kJ/mol
10 kJ/mol100 kJ/mol
kJ/mol

Final Pressure (P2)

0.577268 atm

P1
1.000000 atm
P2
0.577268 atm
T1
373.15 K (100.00°C)
T2
358.15 K (85.00°C)

Clausius-Clapeyron Equation:

ln(P2/P1) = -(Delta Hvap/R) * (1/T2 - 1/T1)

ln(P2/P1):

-0.549449

Understanding the Clausius-Clapeyron Equation

The Clausius-Clapeyron equation describes how vapor pressure changes with temperature during a phase transition. It is derived from thermodynamic principles and assumes that the enthalpy of vaporization is constant over the temperature range. The equation is essential for predicting boiling points at different pressures and for understanding phase equilibria.

Common Enthalpies of Vaporization

SubstanceDelta Hvap (kJ/mol)Boiling Point (°C)
Water40.7100
Ethanol38.678.4
Acetone30.756.1
Benzene30.880.1
Ammonia23.3-33.4

What Is the Clausius-Clapeyron Equation?

The Clausius-Clapeyron equation describes the relationship between vapor pressure and temperature during a phase transition, typically liquid-vapor or solid-vapor. It quantifies how the boiling point of a substance changes with pressure, or equivalently, how vapor pressure increases with temperature. This equation is derived from thermodynamic principles and assumes that the enthalpy of vaporization remains approximately constant over the temperature range of interest.

The equation is particularly important for understanding boiling points at different altitudes and pressures. At sea level, water boils at 100°C because the atmospheric pressure is 1 atm. At high altitudes where pressure is lower, water boils at a lower temperature, which is why cooking times increase at elevation. The Clausius-Clapeyron equation allows precise calculation of these boiling point shifts, which is essential for engineering applications, meteorological modeling, and laboratory work.

The equation also provides a method for determining the enthalpy of vaporization (ΔHvap) from experimental vapor pressure measurements. By measuring vapor pressure at two or more temperatures and applying the Clausius-Clapeyron equation, chemists can extract this important thermodynamic quantity. The enthalpy of vaporization is a key parameter in chemical engineering, refrigeration design, and atmospheric science.

The Clausius-Clapeyron Equation

The Clausius-Clapeyron equation relates the vapor pressures at two different temperatures to the enthalpy of vaporization.

Clausius-Clapeyron Equation

ln(P₂/P₁) = −(ΔHvap/R) × (1/T₂ − 1/T₁)

Where:

  • P₁= Vapor pressure at temperature T₁ (atm)
  • P₂= Vapor pressure at temperature T₂ (atm)
  • T₁= Initial temperature (K)
  • T₂= Final temperature (K)
  • ΔHvap= Enthalpy of vaporization (J/mol)
  • R= Gas constant = 8.314 J/(mol·K)

How to Use This Calculator

This calculator solves for any of the five variables in the Clausius-Clapeyron equation. Here is how to use it:

  1. Select Solve Mode: Choose which variable to calculate — P1, P2, T1, T2, or ΔHvap. The input fields adjust to show only the relevant values.
  2. Enter Known Values: Input the known pressures (in atm), temperatures (in K), and enthalpy of vaporization (in kJ/mol). Sliders and direct entry are both available.
  3. Use Preset Values: Quick-select buttons are available for common substances: water (ΔHvap = 40.7 kJ/mol, BP = 100°C), ethanol (38.6 kJ/mol, BP = 78.4°C), and acetone (30.7 kJ/mol, BP = 56.1°C).
  4. View Results: The calculator displays the solved value along with all other variables. Temperatures are shown in both Kelvin and Celsius for convenience. The ln(P₂/P₁) ratio is also displayed for verification.

Understanding the Results

The calculator solves for whichever variable is unknown, displaying the complete set of five quantities. The pressure results are shown in atmospheres, while temperatures are provided in both Kelvin and Celsius. The ln(P₂/P₁) ratio is the logarithmic pressure ratio that appears in the equation, useful for verifying the calculation.

The enthalpy of vaporization result (when solved for) is displayed in kJ/mol. This value is always positive because vaporization is an endothermic process — energy must be absorbed to convert a liquid to a gas. Higher ΔHvap values indicate stronger intermolecular forces and more energy-intensive vaporization. Water's relatively high ΔHvap (40.7 kJ/mol) is due to its extensive hydrogen bonding network.

When solving for pressure, the result shows how the vapor pressure changes between two temperatures. An increase in temperature always increases vapor pressure, as described by the positive relationship in the equation. The magnitude of this increase depends on ΔHvap — substances with higher enthalpies of vaporization show steeper vapor pressure curves.

Real-World Applications

The Clausius-Clapeyron equation has critical applications in chemical engineering, particularly in the design of distillation columns and separation processes. Distillation exploits differences in vapor pressure to separate liquid mixtures into their components. The equation allows engineers to predict how vapor pressures change with temperature, enabling the design of columns that achieve desired separation efficiencies at specific operating conditions.

Meteorology and atmospheric science rely on the Clausius-Clapeyron equation to model the water vapor content of the atmosphere. The equation predicts that the atmosphere's capacity to hold water vapor increases exponentially with temperature, which is a key feedback mechanism in climate change. As global temperatures rise, the atmosphere holds more water vapor, which is itself a greenhouse gas, amplifying the warming effect.

In refrigeration and air conditioning, the Clausius-Clapeyron equation describes the relationship between the evaporating and condensing pressures of the refrigerant, which determines the system's cooling capacity and efficiency. Pharmaceutical scientists use the equation to predict the volatility of drug compounds and design appropriate storage conditions. Food scientists apply it to understand drying processes, freeze-drying, and the behavior of food during cooking and preservation.

Worked Examples

Boiling Point at Reduced Pressure

Problem:

Water boils at 100°C at 1 atm. What is its boiling point at 0.5 atm? (ΔHvap = 40.7 kJ/mol)

Solution Steps:

  1. 1Identify values: P₁ = 1 atm, T₁ = 373.15 K, P₂ = 0.5 atm, ΔHvap = 40,700 J/mol
  2. 2Apply Clausius-Clapeyron: ln(0.5/1) = −(40,700/8.314) × (1/T₂ − 1/373.15)
  3. 3Calculate: −0.6931 = −4896 × (1/T₂ − 0.002680)
  4. 4Solve: 1/T₂ = 0.002680 + 0.0001416 = 0.002822, T₂ = 354.4 K = 81.2°C

Result:

Water boils at approximately 81.2°C at 0.5 atm, explaining why cooking takes longer at high altitude.

Finding Enthalpy of Vaporization

Problem:

Ethanol's vapor pressure is 0.293 atm at 20°C and 0.675 atm at 40°C. Find ΔHvap.

Solution Steps:

  1. 1Convert temperatures: T₁ = 293.15 K, T₂ = 313.15 K
  2. 2Apply equation: ln(0.675/0.293) = −(ΔHvap/8.314) × (1/313.15 − 1/293.15)
  3. 3Calculate: ln(2.304) = 0.8353 = −(ΔHvap/8.314) × (−0.0002179)
  4. 4Solve: ΔHvap = 0.8353 × 8.314 / 0.0002179 = 31,920 J/mol ≈ 31.9 kJ/mol

Result:

The enthalpy of vaporization of ethanol is approximately 31.9 kJ/mol from these measurements.

Vapor Pressure at Higher Temperature

Problem:

If water's vapor pressure is 0.0313 atm at 25°C, what is it at 50°C? (ΔHvap = 40.7 kJ/mol)

Solution Steps:

  1. 1Convert temperatures: T₁ = 298.15 K, T₂ = 323.15 K
  2. 2Apply equation: ln(P₂/0.0313) = −(40,700/8.314) × (1/323.15 − 1/298.15)
  3. 3Calculate right side: −4896 × (0.003095 − 0.003354) = −4896 × (−0.000259) = 1.268
  4. 4Solve: ln(P₂/0.0313) = 1.268, P₂/0.0313 = e^1.268 = 3.553, P₂ = 0.1112 atm

Result:

The vapor pressure of water at 50°C is approximately 0.111 atm.

Tips & Best Practices

  • Always use absolute temperature (Kelvin) and consistent pressure units in the Clausius-Clapeyron equation.
  • Higher ΔHvap means stronger intermolecular forces and a steeper vapor pressure curve.
  • The equation works best over moderate temperature ranges — it becomes less accurate near the critical point.
  • Use natural logarithm (ln), not base-10 log, in the Clausius-Clapeyron equation.
  • Water's ΔHvap = 40.7 kJ/mol is a useful reference value for comparison with other substances.
  • At high altitudes, reduced atmospheric pressure lowers the boiling point, increasing cooking times.

Frequently Asked Questions

The main assumptions are: (1) the enthalpy of vaporization is constant over the temperature range, (2) the vapor behaves as an ideal gas, and (3) the volume of the liquid is negligible compared to the vapor. These assumptions are generally good for moderate temperature ranges but break down near the critical point where liquid and vapor become indistinguishable.
At high altitudes, atmospheric pressure is lower than 1 atm. The Clausius-Clapeyron equation predicts that water boils at a lower temperature under reduced pressure. Since boiling water cannot exceed its boiling temperature, food cooks more slowly at altitude. For example, at 2000 meters elevation (about 0.8 atm), water boils at approximately 93°C instead of 100°C.
Yes, the equation applies to any phase transition where one phase is a gas. For solid-vapor transitions (sublimation), ΔHvap is replaced by ΔHsub (enthalpy of sublimation), which equals ΔHfus + ΔHvap. The equation then describes how the sublimation pressure changes with temperature, which is relevant for freeze-drying and the behavior of volatile solids.
The enthalpy of vaporization (ΔHvap) is the energy required to convert one mole of liquid to vapor at constant temperature and pressure. It reflects the strength of intermolecular forces — water's high ΔHvap (40.7 kJ/mol) is due to hydrogen bonding. ΔHvap is used in refrigeration design, distillation column sizing, and predicting weather patterns. It also determines how effectively a substance can cool by evaporation.
Both phenomena arise from the effect of solutes or pressure on vapor pressure. Boiling point elevation occurs because a solute lowers the solvent's vapor pressure, requiring a higher temperature to reach atmospheric pressure. The Clausius-Clapeyron equation quantifies how vapor pressure changes with temperature. Together, they explain why adding salt to water raises its boiling point and how pressure affects boiling in industrial processes.

Sources & References

Last updated: 2026-06-06

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Editorial Note

MyCalcBuddy Editorial Team

This page is maintained as an educational calculator reference.

Source

Formula Source: Chemistry: The Central Science

by Brown, LeMay, Bursten

UpdatedLast reviewed: May 2026
CheckedFormula checks are based on standard references and internal QA review.